C# (CSharp) FeedbackManager.GetListID示例

示例#1

文件： List.aspx.cs 项目： 303699796/UserFB

        protected void Btn_Choos_Click(object sender, EventArgs e)
        {
            Button      btn = sender as Button;
            GridViewRow row = btn.Parent.Parent as GridViewRow;
            string      a   = row.Cells[0].ToString();

            string b = Convert.ToString(this.GridView1.DataKeys[row.DataItemIndex].Values[0]);//获得DataKeys的值   

            Labeltest.Text = b;


            Model.Feedback      feedback = new Model.Feedback();
            BLL.FeedbackManager Fmanager = new FeedbackManager();
            string Str1 = "feedbackID='" + Labeltest.Text + "'";
            string s    = Fmanager.GetListID(Str1);

            LabelName.Text = s;

            GridView2.Columns[9].Visible = true;
        }