Пример #1
0
        public ActionResult GetFriend(int[] ids)
        {
            List <int> getFriendIds = friendManager
                                      .List(x => x.UserId == SessionManager.User.Id && ids.Contains(x.FriendId)).Select(x => x.User.Id)
                                      .ToList();

            return(Json(new { result = getFriendIds }));
        }