示例#1
0
        /// <summary>
        /// find nearest point to vertex in collision graph
        /// </summary>
        double MinCollisionConstraintDistance(int vid, double collision_radius)
        {
            if (collision_edge_hash == null)
            {
                return(double.MaxValue);
            }

            Vector2d pos = Graph.GetVertex(vid);
            Vector2d a = Vector2d.Zero, b = Vector2d.Zero;
            var      result = collision_edge_hash.FindNearestInSquaredRadius(pos, collision_radius * collision_radius,
                                                                             (eid) => {
                CollisionGraph.GetEdgeV(eid, ref a, ref b);
                return(Segment2d.FastDistanceSquared(ref a, ref b, ref pos));
            }
                                                                             );

            return((result.Key == -1) ? double.MaxValue : Math.Sqrt(result.Value));
        }
示例#2
0
        /// <summary>
        /// Find nearest point to vertex vid in graph, but filter out **connected** neighbourhood within self_radius
        /// </summary>
        double MinSelfSegDistance(int vid, double self_radius)
        {
            Vector2d pos = Graph.GetVertex(vid);

            List <int> ignore_edges = new List <int>(16);

            FindConnectedEdgesInRadius(vid, self_radius * self_radius, ignore_edges);

            Vector2d a = Vector2d.Zero, b = Vector2d.Zero;
            var      result = edge_hash.FindNearestInSquaredRadius(pos, self_radius * self_radius,
                                                                   (eid) => {
                Graph.GetEdgeV(eid, ref a, ref b);
                return(Segment2d.FastDistanceSquared(ref a, ref b, ref pos));
            },
                                                                   (eid) => { return(ignore_edges.Contains(eid)); }
                                                                   );

            return((result.Key == -1) ? double.MaxValue : Math.Sqrt(result.Value));
        }