public System.Threading.Tasks.Task <FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse> UploadFileAsync(string FileName, long Length, System.IO.Stream FileByteStream)
{
FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo inValue = new FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo();
inValue.FileName = FileName;
inValue.Length = Length;
inValue.FileByteStream = FileByteStream;
return(((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).UploadFileAsync(inValue));
}
public void UploadFile(string FileName, long Length, System.IO.Stream FileByteStream)
{
FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo inValue = new FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo();
inValue.FileName = FileName;
inValue.Length = Length;
inValue.FileByteStream = FileByteStream;
FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse retVal = ((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).UploadFile(inValue);
}
public long DownloadFile(ref string FileName, out System.IO.Stream FileByteStream)
{
FileShareConsoleClient.FIleTransferServiceReference.DownloadRequest inValue = new FileShareConsoleClient.FIleTransferServiceReference.DownloadRequest();
inValue.FileName = FileName;
FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo retVal = ((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).DownloadFile(inValue);
FileName = retVal.FileName;
FileByteStream = retVal.FileByteStream;
return(retVal.Length);
}
System.Threading.Tasks.Task <FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse> FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService.UploadFileAsync(FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo request)
{
return(base.Channel.UploadFileAsync(request));
}
FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService.UploadFile(FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo request)
{
return(base.Channel.UploadFile(request));
}
