public System.Threading.Tasks.Task <FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse> UploadFileAsync(string FileName, long Length, System.IO.Stream FileByteStream) { FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo inValue = new FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo(); inValue.FileName = FileName; inValue.Length = Length; inValue.FileByteStream = FileByteStream; return(((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).UploadFileAsync(inValue)); }
public void UploadFile(string FileName, long Length, System.IO.Stream FileByteStream) { FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo inValue = new FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo(); inValue.FileName = FileName; inValue.Length = Length; inValue.FileByteStream = FileByteStream; FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse retVal = ((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).UploadFile(inValue); }
public long DownloadFile(ref string FileName, out System.IO.Stream FileByteStream) { FileShareConsoleClient.FIleTransferServiceReference.DownloadRequest inValue = new FileShareConsoleClient.FIleTransferServiceReference.DownloadRequest(); inValue.FileName = FileName; FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo retVal = ((FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService)(this)).DownloadFile(inValue); FileName = retVal.FileName; FileByteStream = retVal.FileByteStream; return(retVal.Length); }
System.Threading.Tasks.Task <FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse> FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService.UploadFileAsync(FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo request) { return(base.Channel.UploadFileAsync(request)); }
FileShareConsoleClient.FIleTransferServiceReference.UploadFileResponse FileShareConsoleClient.FIleTransferServiceReference.IFileTransferService.UploadFile(FileShareConsoleClient.FIleTransferServiceReference.RemoteFileInfo request) { return(base.Channel.UploadFile(request)); }