public static OpeningSoonModel Deserialize(string json) { if (json == null) { return(null); } var items = JsonConvert.DeserializeObject <IEnumerable <OpeningTime> >(json); var m = new OpeningSoonModel(); m.openingTimes = items; return(m); }
public object ConvertSourceToObject(Umbraco.Core.Models.PublishedContent.PublishedPropertyType propertyType, object source, bool preview) { return(OpeningSoonModel.Deserialize((string)source)); }