public static OpeningSoonModel Deserialize(string json)
{
if (json == null)
{
return(null);
}
var items = JsonConvert.DeserializeObject <IEnumerable <OpeningTime> >(json);
var m = new OpeningSoonModel();
m.openingTimes = items;
return(m);
}
public object ConvertSourceToObject(Umbraco.Core.Models.PublishedContent.PublishedPropertyType propertyType, object source, bool preview)
{
return(OpeningSoonModel.Deserialize((string)source));
}
