예제 #1
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		} // SMS


		/// <summary>
		/// This is the divide-and-conquer implementation of the longes common-subsequence (LCS) 
		/// algorithm.
		/// The published algorithm passes recursively parts of the A and B sequences.
		/// To avoid copying these arrays the lower and upper bounds are passed while the sequences stay constant.
		/// </summary>
		/// <param name="DataA">sequence A</param>
		/// <param name="LowerA">lower bound of the actual range in DataA</param>
		/// <param name="UpperA">upper bound of the actual range in DataA (exclusive)</param>
		/// <param name="DataB">sequence B</param>
		/// <param name="LowerB">lower bound of the actual range in DataB</param>
		/// <param name="UpperB">upper bound of the actual range in DataB (exclusive)</param>
		/// <param name="DownVector">a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons.</param>
		/// <param name="UpVector">a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons.</param>
		private static void LongesCommonSequence( DiffData DataA, int LowerA, int UpperA, DiffData DataB, int LowerB, int UpperB, int[] DownVector, int[] UpVector )
		{
			// Debug.Write(2, "LCS", String.Format("Analyse the box: A[{0}-{1}] to B[{2}-{3}]", LowerA, UpperA, LowerB, UpperB));

			// Fast walkthrough equal lines at the start
			while ( LowerA < UpperA && LowerB < UpperB && DataA.data[LowerA] == DataB.data[LowerB] )
			{
				LowerA++;
				LowerB++;
			}

			// Fast walkthrough equal lines at the end
			while ( LowerA < UpperA && LowerB < UpperB && DataA.data[UpperA - 1] == DataB.data[UpperB - 1] )
			{
				--UpperA;
				--UpperB;
			}

			if ( LowerA == UpperA )
			{
				// mark as inserted lines.
				while ( LowerB < UpperB )
					DataB.modified[LowerB++] = true;

			}
			else if ( LowerB == UpperB )
			{
				// mark as deleted lines.
				while ( LowerA < UpperA )
					DataA.modified[LowerA++] = true;

			}
			else
			{
				// Find the middle snakea and length of an optimal path for A and B
				SmsReturnData smsrd = ShortestMiddleSnake( DataA, LowerA, UpperA, DataB, LowerB, UpperB, DownVector, UpVector );
				// Debug.Write(2, "MiddleSnakeData", String.Format("{0},{1}", smsrd.x, smsrd.y));

				// The path is from LowerX to (x,y) and (x,y) to UpperX
				LongesCommonSequence( DataA, LowerA, smsrd.x, DataB, LowerB, smsrd.y, DownVector, UpVector );
				LongesCommonSequence( DataA, smsrd.x, UpperA, DataB, smsrd.y, UpperB, DownVector, UpVector );  // 2002.09.20: no need for 2 points 
			}
		} // LongesCommonSequence
예제 #2
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		/// <summary>
		/// Find the difference in 2 text documents, comparing by textlines.
		/// The algorithm itself is comparing 2 arrays of numbers so when comparing 2 text documents
		/// each line is converted into a (hash) number. This hash-value is computed by storing all
		/// textlines into a common hashtable so i can find dublicates in there, and generating a 
		/// new number each time a new textline is inserted.
		/// </summary>
		/// <param name="TextA">A-version of the text (usualy the old one)</param>
		/// <param name="TextB">B-version of the text (usualy the new one)</param>
		/// <param name="trimSpace">When set to true, all leading and trailing whitespace characters are stripped out before the comparation is done.</param>
		/// <param name="ignoreSpace">When set to true, all whitespace characters are converted to a single space character before the comparation is done.</param>
		/// <param name="ignoreCase">When set to true, all characters are converted to their lowercase equivivalence before the comparation is done.</param>
		/// <returns>Returns a array of Items that describe the differences.</returns>
		public static Item[] DiffText( List<string> TextA, List<string> TextB, bool trimSpace, bool ignoreSpace, bool ignoreCase )
		{
			Hashtable codeHash = new Hashtable( TextA.Count + TextB.Count );

			DiffData DataA = new DiffData( GenerateDiffCodes( TextA, codeHash, trimSpace, ignoreSpace, ignoreCase ) );

			DiffData DataB = new DiffData( GenerateDiffCodes( TextB, codeHash, trimSpace, ignoreSpace, ignoreCase ) );

			codeHash = null; // free up hashtable memory (maybe)

			int combinedLength = DataA.Length + DataB.Length + 1;
			/// vector for the (0,0) to (x,y) search
			int[] DownVector = new int[2 * combinedLength + 2];
			/// vector for the (u,v) to (N,M) search
			int[] UpVector = new int[2 * combinedLength + 2];

			LongesCommonSequence( DataA, 0, DataA.Length, DataB, 0, DataB.Length, DownVector, UpVector );

			Optimize( DataA );
			Optimize( DataB );
			return CreateDiffs( DataA, DataB );
		} // DiffText
예제 #3
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		} // DiffText


		/// <summary>
		/// If a sequence of modified lines starts with a line that contains the same content
		/// as the line that appends the changes, the difference sequence is modified so that the
		/// appended line and not the starting line is marked as modified.
		/// This leads to more readable diff sequences when comparing text files.
		/// </summary>
		/// <param name="Data">A Diff data buffer containing the identified changes.</param>
		private static void Optimize( DiffData Data )
		{
			int StartPos, EndPos;

			StartPos = 0;
			while ( StartPos < Data.Length )
			{
				while ( (StartPos < Data.Length) && (Data.modified[StartPos] == false) )
					StartPos++;
				EndPos = StartPos;
				while ( (EndPos < Data.Length) && (Data.modified[EndPos] == true) )
					EndPos++;

				if ( (EndPos < Data.Length) && (Data.data[StartPos] == Data.data[EndPos]) )
				{
					Data.modified[StartPos] = false;
					Data.modified[EndPos] = true;
				}
				else
				{
					StartPos = EndPos;
				} // if
			} // while
		} // Optimize
예제 #4
0
		} // GenerateDiffCodes




		/// <summary>
		/// This is the algorithm to find the Shortest Middle Snake (SMS).
		/// </summary>
		/// <param name="DataA">sequence A</param>
		/// <param name="LowerA">lower bound of the actual range in DataA</param>
		/// <param name="UpperA">upper bound of the actual range in DataA (exclusive)</param>
		/// <param name="DataB">sequence B</param>
		/// <param name="LowerB">lower bound of the actual range in DataB</param>
		/// <param name="UpperB">upper bound of the actual range in DataB (exclusive)</param>
		/// <param name="DownVector">a vector for the (0,0) to (x,y) search. Passed as a parameter for speed reasons.</param>
		/// <param name="UpVector">a vector for the (u,v) to (N,M) search. Passed as a parameter for speed reasons.</param>
		/// <returns>a MiddleSnakeData record containing x,y and u,v</returns>
		private static SmsReturnData ShortestMiddleSnake( DiffData DataA, int LowerA, int UpperA, DiffData DataB, int LowerB, int UpperB,
		  int[] DownVector, int[] UpVector )
		{

			SmsReturnData ret;
			int MAX = DataA.Length + DataB.Length + 1;

			int DownK = LowerA - LowerB; // the k-line to start the forward search
			int UpK = UpperA - UpperB; // the k-line to start the reverse search

			int Delta = (UpperA - LowerA) - (UpperB - LowerB);
			bool oddDelta = (Delta & 1) != 0;

			// The vectors in the publication accepts negative indexes. the vectors implemented here are 0-based
			// and are access using a specific offset: UpOffset UpVector and DownOffset for DownVektor
			int DownOffset = MAX - DownK;
			int UpOffset = MAX - UpK;

			int MaxD = ((UpperA - LowerA + UpperB - LowerB) / 2) + 1;

			// Debug.Write(2, "SMS", String.Format("Search the box: A[{0}-{1}] to B[{2}-{3}]", LowerA, UpperA, LowerB, UpperB));

			// init vectors
			DownVector[DownOffset + DownK + 1] = LowerA;
			UpVector[UpOffset + UpK - 1] = UpperA;

			for ( int D = 0; D <= MaxD; D++ )
			{

				// Extend the forward path.
				for ( int k = DownK - D; k <= DownK + D; k += 2 )
				{
					// Debug.Write(0, "SMS", "extend forward path " + k.ToString());

					// find the only or better starting point
					int x, y;
					if ( k == DownK - D )
					{
						x = DownVector[DownOffset + k + 1]; // down
					}
					else
					{
						x = DownVector[DownOffset + k - 1] + 1; // a step to the right
						if ( (k < DownK + D) && (DownVector[DownOffset + k + 1] >= x) )
							x = DownVector[DownOffset + k + 1]; // down
					}
					y = x - k;

					// find the end of the furthest reaching forward D-path in diagonal k.
					while ( (x < UpperA) && (y < UpperB) && (DataA.data[x] == DataB.data[y]) )
					{
						x++;
						y++;
					}
					DownVector[DownOffset + k] = x;

					// overlap ?
					if ( oddDelta && (UpK - D < k) && (k < UpK + D) )
					{
						if ( UpVector[UpOffset + k] <= DownVector[DownOffset + k] )
						{
							ret.x = DownVector[DownOffset + k];
							ret.y = DownVector[DownOffset + k] - k;
							// ret.u = UpVector[UpOffset + k];      // 2002.09.20: no need for 2 points 
							// ret.v = UpVector[UpOffset + k] - k;
							return (ret);
						} // if
					} // if

				} // for k

				// Extend the reverse path.
				for ( int k = UpK - D; k <= UpK + D; k += 2 )
				{
					// Debug.Write(0, "SMS", "extend reverse path " + k.ToString());

					// find the only or better starting point
					int x, y;
					if ( k == UpK + D )
					{
						x = UpVector[UpOffset + k - 1]; // up
					}
					else
					{
						x = UpVector[UpOffset + k + 1] - 1; // left
						if ( (k > UpK - D) && (UpVector[UpOffset + k - 1] < x) )
							x = UpVector[UpOffset + k - 1]; // up
					} // if
					y = x - k;

					while ( (x > LowerA) && (y > LowerB) && (DataA.data[x - 1] == DataB.data[y - 1]) )
					{
						x--;
						y--; // diagonal
					}
					UpVector[UpOffset + k] = x;

					// overlap ?
					if ( !oddDelta && (DownK - D <= k) && (k <= DownK + D) )
					{
						if ( UpVector[UpOffset + k] <= DownVector[DownOffset + k] )
						{
							ret.x = DownVector[DownOffset + k];
							ret.y = DownVector[DownOffset + k] - k;
							// ret.u = UpVector[UpOffset + k];     // 2002.09.20: no need for 2 points 
							// ret.v = UpVector[UpOffset + k] - k;
							return (ret);
						} // if
					} // if

				} // for k

			} // for D

			throw new ApplicationException( "the algorithm should never come here." );
		} // SMS