예제 #1
0
        static IEnumerable <(PlaneCoordinate Coordinate, int MapIndex)> ExtendPattern
            (IList <int> decodePattern, int width, int height, short plane, int planePatternSize, int patternSize)
        {
            int imageSize  = width * height;
            int pixelIndex = 0;
            int repeat     = 0;

            while (pixelIndex < width * height)
            {
                int extendSize = Math.Min(planePatternSize, imageSize);
                for (int i = 0; i < extendSize; i++)
                {
                    var   bitIndex = decodePattern[pixelIndex % planePatternSize];
                    short x        = (short)(pixelIndex % width);
                    short y        = (short)(pixelIndex / width);
                    var   coord    = new PlaneCoordinate(x, y, plane);
                    var   index    = bitIndex + repeat * patternSize;

                    yield return(coord, index);

                    pixelIndex++;
                }

                repeat++;
            }
        }
예제 #2
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 public int GetEncodeIndex(PlaneCoordinate coordinate)
 {
     if (_encodePattern.TryGetValue(coordinate, out var bitIndex))
     {
         return(bitIndex);
     }
     throw new KeyNotFoundException($"{nameof(GetEncodeIndex)} argument {nameof(coordinate)} ({coordinate.X}, {coordinate.Y}, {coordinate.P}) was found in the encoder remapping");
 }
예제 #3
0
파일: ClosestPair.cs 프로젝트: scripni/algo
        private static Tuple<PlaneCoordinate, PlaneCoordinate> DivideConquerClosestPair(PlaneCoordinate[] coordinates)
        {
            // sort by x and y
            Sorter<double> mergeSort = new MergeSort<double>();
            double[] px = mergeSort.Sort(coordinates.Select(p => p.X).ToArray());
            double[] py = mergeSort.Sort(coordinates.Select(p => p.Y).ToArray());

            return FindClosestPair(px, py);
        }
예제 #4
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        public void FindClosestPair_TwoPoints_ReturnsExpected()
        {
            // arrange
            PlaneCoordinate x = new PlaneCoordinate(0, 0);
            PlaneCoordinate y = new PlaneCoordinate(0, 1);
            ClosestPair algorithm = new ClosestPair();

            // act
            Tuple<PlaneCoordinate, PlaneCoordinate> closestPair = algorithm.FindClosestPair(new[] { x, y });

            // assert
            Assert.AreEqual(closestPair.Item1, x);
            Assert.AreEqual(closestPair.Item2, y);
        }
예제 #5
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        public void FindClosestPair_AllAxesDifferent_ReturnsExpected()
        {
            // arrange
            PlaneCoordinate x = new PlaneCoordinate(0, 1);
            PlaneCoordinate y = new PlaneCoordinate(1, 5);
            PlaneCoordinate z = new PlaneCoordinate(4, -10);
            ClosestPair algorithm = new ClosestPair();

            // act
            Tuple<PlaneCoordinate, PlaneCoordinate> closestPair = algorithm.FindClosestPair(new[] { x, y, z });

            // assert
            Assert.AreEqual(closestPair.Item1, x);
            Assert.AreEqual(closestPair.Item2, y);
        }
예제 #6
0
파일: ClosestPair.cs 프로젝트: scripni/algo
        /// <summary>
        /// Brute-force closest pair implementation.
        /// </summary>
        /// <param name="coordinates">The coordinates.</param>
        /// <returns>Closest pair.</returns>
        private static Tuple<PlaneCoordinate, PlaneCoordinate> BruteForceClosestPair(PlaneCoordinate[] coordinates)
        {
            if (coordinates == null)
            {
                throw new ArgumentNullException("coordinates");
            }

            if (coordinates.Length < 2)
            {
                throw new ArgumentException("At least two points must be passed.", "coordinates");
            }

            double minDistance = double.MaxValue;
            int minI = -1, minJ = -1;
            for (int i = 0; i < coordinates.Length; i++)
            {
                for (int j = i; j < coordinates.Length; j++)
                {
                    if (i == j)
                    {
                        continue;
                    }

                    double distance = coordinates[i].Distance(coordinates[j]);
                    if (distance < minDistance)
                    {
                        minI = i;
                        minJ = j;
                        minDistance = distance;
                    }
                }
            }

            return new Tuple<PlaneCoordinate, PlaneCoordinate>(
                coordinates[minI], coordinates[minJ]);
        }
예제 #7
0
파일: ClosestPair.cs 프로젝트: scripni/algo
        private static Tuple<PlaneCoordinate, PlaneCoordinate> FindClosestPair(double[] px, double[] py)
        {
            if (px.Length == 2)
            {
                return new Tuple<PlaneCoordinate, PlaneCoordinate>(new PlaneCoordinate(px[0], py[0]),
                    new PlaneCoordinate(px[1], py[1]));
            }

            double minDistance;

            if (px.Length == 3)
            {
                PlaneCoordinate a = new PlaneCoordinate(px[0], py[0]);
                PlaneCoordinate b = new PlaneCoordinate(px[1], py[1]);
                PlaneCoordinate c = new PlaneCoordinate(px[2], py[2]);

                double ab = a.Distance(b);
                double ac = a.Distance(c);
                double bc = b.Distance(c);

                minDistance = Math.Min(ab, Math.Min(ac, bc));

                if (minDistance == ab)
                {
                    return new Tuple<PlaneCoordinate, PlaneCoordinate>(a, b);
                }

                if (minDistance == ac)
                {
                    return new Tuple<PlaneCoordinate, PlaneCoordinate>(a, c);
                }

                return new Tuple<PlaneCoordinate, PlaneCoordinate>(b, c);
            }

            // divide
            int middle = px.Length / 2;

            // left
            double[] qpx = new double[middle];
            Array.Copy(px, qpx, qpx.Length);
            double[] qpy = new double[middle];
            Array.Copy(py, qpy, qpy.Length);

            // right
            double[] rpx = new double[px.Length - middle];
            Array.Copy(px, middle, rpx, 0, rpx.Length);
            double[] rpy = new double[px.Length - middle];
            Array.Copy(py, middle, rpy, 0, rpy.Length);

            // conquer
            Tuple<PlaneCoordinate, PlaneCoordinate> p1q1 = FindClosestPair(qpx, qpy);
            double dist1 = p1q1.Item1.Distance(p1q1.Item2);
            Tuple<PlaneCoordinate, PlaneCoordinate> p2q2 = FindClosestPair(rpx, rpy);
            double dist2 = p2q2.Item1.Distance(p2q2.Item2);

            minDistance = Math.Min(dist1, dist2);
            Tuple<PlaneCoordinate, PlaneCoordinate> p3q3 = ClosestPairSplit(px, py, minDistance);
            double dist3 = p3q3.Item1.Distance(p3q3.Item2);

            minDistance = Math.Min(minDistance, dist3);

            if (minDistance == dist1)
            {
                return p1q1;
            }

            if (minDistance == dist2)
            {
                return p2q2;
            }

            return p3q3;
        }
예제 #8
0
파일: ClosestPair.cs 프로젝트: scripni/algo
        /// <summary>
        /// Finds the closest pair in a set of coordinates.
        /// </summary>
        /// <param name="coordinates">The coordinates.</param>
        /// <returns>Closest pair.</returns>
        public Tuple<PlaneCoordinate, PlaneCoordinate> FindClosestPair(
			PlaneCoordinate[] coordinates)
        {
            return BruteForceClosestPair(coordinates);
        }