static string Mode(BigNumber[] NumberSeries)
{
//仅限于寻找有序数列中的众数
//多个众数时返回最小的众数
double MaxCount = 0;
double CurrentCount = 0;
BigNumber MaxNumber = new BigNumber("0");
BigNumber CurrentNumber = new BigNumber("0");
int len = NumberSeries.Length;
for (int i = 1; i < len; i++)
{
if (CompareNumber.Compare(NumberSeries[i - 1], NumberSeries[i]) == 0)
{
CurrentCount++;
if (CurrentCount > MaxCount)
{
MaxCount = CurrentCount;
MaxNumber = NumberSeries[i];
}
}
else
{
CurrentCount = 0;
}
}
if (MaxCount == 0)
{
return("NA");
}
else
{
return(MaxNumber.ToString());
}
}
static void Main(string[] args)
{
CompareNumber comNumber = new CompareNumber();
Number number = new Number();
number.getInputNumber = 1;
Result result = comNumber.checkNumber(number.getInputNumber);
Console.WriteLine(result.getResult);
}
static void Sort(int n, BigNumber[] NumberSeries)
{
BigNumber temp = new BigNumber("0");
if (n <= 1)
{
return;
}
for (int i = 0; i < n - 1; i++)
{
if (CompareNumber.Compare(NumberSeries[i], NumberSeries[i + 1]) == 1)
{
temp = NumberSeries[i + 1];
NumberSeries[i + 1] = NumberSeries[i];
NumberSeries[i] = temp;
}
Sort(n - 1, NumberSeries);
}
}
static string HT(BigNumber H0, BigNumber[] NumberSeries, double significance, int tail)
{
//Hypothesis Testing假设检验
string result = ParaEasti(NumberSeries, significance, tail);
//今天太晚了，我只写了双侧，假定tail = 2，剩下的麻烦你们拓展啦，加油！
//假设检验当然不一定要在原空空间里做，我这里只是想演示一下如何读取置信区间。
char[] separator = { ',' };
string[] intervals = result.Split(separator);
BigNumber lower = new BigNumber(intervals[0]);
BigNumber upper = new BigNumber(intervals[1]);
if (CompareNumber.Compare(lower, H0) == -1 && CompareNumber.Compare(upper, H0) == 1)
{
return("不拒绝原假设");
}
else
{
return("拒绝原假设");
}
}
