static string Mode(BigNumber[] NumberSeries) { //仅限于寻找有序数列中的众数 //多个众数时返回最小的众数 double MaxCount = 0; double CurrentCount = 0; BigNumber MaxNumber = new BigNumber("0"); BigNumber CurrentNumber = new BigNumber("0"); int len = NumberSeries.Length; for (int i = 1; i < len; i++) { if (CompareNumber.Compare(NumberSeries[i - 1], NumberSeries[i]) == 0) { CurrentCount++; if (CurrentCount > MaxCount) { MaxCount = CurrentCount; MaxNumber = NumberSeries[i]; } } else { CurrentCount = 0; } } if (MaxCount == 0) { return("NA"); } else { return(MaxNumber.ToString()); } }
static void Main(string[] args) { CompareNumber comNumber = new CompareNumber(); Number number = new Number(); number.getInputNumber = 1; Result result = comNumber.checkNumber(number.getInputNumber); Console.WriteLine(result.getResult); }
static void Sort(int n, BigNumber[] NumberSeries) { BigNumber temp = new BigNumber("0"); if (n <= 1) { return; } for (int i = 0; i < n - 1; i++) { if (CompareNumber.Compare(NumberSeries[i], NumberSeries[i + 1]) == 1) { temp = NumberSeries[i + 1]; NumberSeries[i + 1] = NumberSeries[i]; NumberSeries[i] = temp; } Sort(n - 1, NumberSeries); } }
static string HT(BigNumber H0, BigNumber[] NumberSeries, double significance, int tail) { //Hypothesis Testing假设检验 string result = ParaEasti(NumberSeries, significance, tail); //今天太晚了,我只写了双侧,假定tail = 2,剩下的麻烦你们拓展啦,加油! //假设检验当然不一定要在原空空间里做,我这里只是想演示一下如何读取置信区间。 char[] separator = { ',' }; string[] intervals = result.Split(separator); BigNumber lower = new BigNumber(intervals[0]); BigNumber upper = new BigNumber(intervals[1]); if (CompareNumber.Compare(lower, H0) == -1 && CompareNumber.Compare(upper, H0) == 1) { return("不拒绝原假设"); } else { return("拒绝原假设"); } }