コード例 #1
0
 /// <summary>
 /// Determines if the given concrete type is associated to a graph type of the supplied kind. This
 /// method will perform a <see cref="TypeKind"/> coersion if possible.
 /// </summary>
 /// <param name="type">The concrete type to search for.</param>
 /// <param name="kind">The graph type kind to look for.</param>
 /// <returns><c>true</c> if a graph type exists, <c>false</c> otherwise.</returns>
 public bool Contains(Type type, TypeKind?kind = null)
 {
     type = GraphQLProviders.ScalarProvider.EnsureBuiltInTypeReference(type);
     if (_graphTypesByConcreteType.TryGetValue(type, out var typeSet))
     {
         var resolvedKind = kind ?? GraphValidation.ResolveTypeKind(type);
         return(typeSet.ContainsKey(resolvedKind));
     }
     else
     {
         return(false);
     }
 }
コード例 #2
0
 /// <summary>
 /// Retrieves the concrete types that this instance may return or make use of in a graph query.
 /// </summary>
 /// <returns>IEnumerable&lt;Type&gt;.</returns>
 public IEnumerable <DependentType> RetrieveRequiredTypes()
 {
     if (this.ArgumentModifiers.IsSourceParameter())
     {
         // source parameters should not be injected into the object graph
         // so they have no dependents
         return(Enumerable.Empty <DependentType>());
     }
     else
     {
         var expectedTypeKind = GraphValidation.ResolveTypeKind(this.ObjectType, TypeKind.INPUT_OBJECT);
         return(new DependentType(this.ObjectType, expectedTypeKind).AsEnumerable());
     }
 }
コード例 #3
0
        /// <summary>
        /// Attempts to find the graph type of a given kind for the supplied concrete type. Returns null if no type is found. This
        /// method will perform a <see cref="TypeKind"/> coersion if possible.
        /// </summary>
        /// <param name="type">The concrete type to search with.</param>
        /// <param name="kind">The kind of graph type to search for. If not supplied the schema will attempt to automatically
        /// resolve the correct kind from the given <see cref="Type"/>.</param>
        /// <returns>IGraphType.</returns>
        public IGraphType FindGraphType(Type type, TypeKind?kind = null)
        {
            Validation.ThrowIfNull(type, nameof(type));

            type = GraphQLProviders.ScalarProvider.EnsureBuiltInTypeReference(type);
            var resolvedKind = GraphValidation.ResolveTypeKind(type, kind);

            if (_graphTypesByConcreteType.TryGetValue(type, out var typeSet))
            {
                if (typeSet.TryGetValue(resolvedKind, out var graphType))
                {
                    return(graphType);
                }
            }

            return(null);
        }
コード例 #4
0
        /// <summary>
        /// Parses the provided type, extracting the metadata to used in type generation for the object graph.
        /// </summary>
        /// <param name="objectType">The type of the object to parse.</param>
        /// <param name="kind">The kind of graph type to parse for.</param>
        /// <returns>IGraphTypeTemplate.</returns>
        public IGraphTypeTemplate ParseType(Type objectType, TypeKind?kind = null)
        {
            Validation.ThrowIfNull(objectType, nameof(objectType));

            var typeKind = GraphValidation.ResolveTypeKind(objectType, kind);
            var typeKey  = Tuple.Create(typeKind, objectType);

            if (_knownObjects.TryGetValue(typeKey, out var template) && this.CacheTemplates)
            {
                return(template);
            }

            if (GraphQLProviders.ScalarProvider.IsScalar(objectType))
            {
                throw new GraphTypeDeclarationException(
                          $"The type '{objectType.FriendlyName()}' is a known scalar type. Scalars must be explicitly defined and cannot be templated.",
                          objectType);
            }

            if (Validation.IsCastable <IGraphUnionProxy>(objectType))
            {
                throw new GraphTypeDeclarationException(
                          $"The union proxy '{objectType.FriendlyName()}' cannot be directly parsed as a graph type. Double check " +
                          "your field attribute declarations'.",
                          objectType);
            }

            GraphValidation.IsValidGraphType(objectType, true);

            template = this.MakeTemplate(objectType, typeKind);
            template.Parse();
            template.ValidateOrThrow();

            if (this.CacheTemplates)
            {
                _knownObjects.TryAdd(typeKey, template);
            }

            return(template);
        }
コード例 #5
0
 /// <summary>
 /// Creates a <see cref="IGraphType" /> representing the union this field should masquerade as in the object graph.
 /// Returns null if no union is declared for this field.
 /// </summary>
 /// <returns>IGraphType.</returns>
 public virtual IEnumerable <DependentType> RetrieveRequiredTypes()
 {
     // a base field knows, at most, about the return object type it is dependent on
     return(this.PossibleTypes?.Select(x => new DependentType(x, GraphValidation.ResolveTypeKind(x, this.Kind)))
            ?? Enumerable.Empty <DependentType>());
 }