/// <summary>
/// Outputs a list of the relations that this class has toward other classes.
/// </summary>
/// <param name="builder">the stringbuilder to render to</param>
/// <returns></returns>
public StringBuilder OutputRelations(StringBuilder builder)
{
foreach (var use in Uses.Where(u => u.Relevant))
{
//Do not pretend to be 'using' a type that is equal to the inheriting types.
if (Inherits.Any(i => i.TypeName == use.TypeName))
{
continue; //don't output if using superclass, this is not a useful notation.
}
//Todo: any reference to a complex type (i.e. class) tends to get displayed as a compound reference when it is a member in\
//the class; this is not a correct logic; needs to be expanded for example by checking the contents of the 'refid' in question (if it is nested, it
//could probably be assumed to be a more than one relationship; i.e. composition)
use.Compound = false;
string arrowhead;
if (use.Compound)
{
arrowhead = "arrowhead=odiamond";
builder.AppendLine($@"""{ use.TypeName.NoNameSpaces()}""->""{Name.NoNameSpaces()}"" [{arrowhead} {(use.node is InterfaceNode ? "style =dashed" : "")} label=""{use.DeclaredName.NoNameSpaces()}"" ]");
}
else
{
arrowhead = "arrowhead = normal";
builder.AppendLine($@"""{ Name.NoNameSpaces()}""->""{use.TypeName.NoNameSpaces()}"" [{arrowhead} {(use.node is InterfaceNode ? "style =dashed" : "")} label=""{use.DeclaredName.NoNameSpaces()}"" ]");
}
//Create the actual arrow from this node to the used one, if the used node is an interface, make the line dashed to indicate dependency
}
foreach (var inheritee in Inherits)
{
builder.AppendLine(@" edge [arrowtail = ""empty"" ]");
builder.AppendLine($"\"{inheritee.TypeName.NoNameSpaces()}\"->\"{Name.NoNameSpaces()}\" [{ (inheritee.node is InterfaceNode ? "style=dashed" : "style=solid")} { (inheritee == null ? ", label=\"??\"" : " ") } dir=back ]");
}
return(builder);
}
