public void NextActionAI()
{
//保证游戏状态是游戏中
if (userGUI.gameState == -1 || userGUI.gameState == 1)
{
return;
}
//得到当前状态
//计算所有在左边的牧师/恶魔
int numDevilLeft = leftBank.getNumDevil(), numPriestLeft = leftBank.getNumPriest();
int numDevilBoat = boat.getNumDevil(), numPriestBoat = boat.getNumPriest();
if (boat.getState() == 1)
{
numDevilLeft += numDevilBoat;
numPriestLeft += numPriestBoat;
}
Debug.Log("numDevilLeft " + numDevilLeft);
Debug.Log("numPriestLeft " + numPriestLeft);
int boatPos = boat.getState();
//获取下一个状态
int[] next = ai.getNextAction(numDevilLeft, numPriestLeft, boat.getState());
Debug.Log("next[0] " + next[0]);
Debug.Log("next[1] " + next[1]);
//其实next就表示要放在船上的人
//转换到下一个状态
/*
* numDveilToBoat = 0, numPriestToBoat = 0 要变得和next一样
* 先boat -> 岸
* 第一个是P
* next[0] > 0 留着 numPriestToBoat++
* next[0] = 0 放回去
* 第一个是D
* next[1] 同上 numDveilToBoat++
* 第二个是P
* next[0] = 2 且 numPriestToBoat = 1 留着
* next[0] = 1 放回去
* 第二个是D
* 同上
* 再 岸 -> boat
* 看一下 num和next没满足的，放岸上的去船上即可
*/
int numPriestToBoat = 0, numDevilToBoat = 0;
int[] personOnBoat = boat.getPersonOnBoat();
if (personOnBoat[0] >= 3 && personOnBoat[0] <= 6) //第一个是P
{
if (next[0] > 0) //P保持不动
{
numPriestToBoat++;
}
else if (next[0] == 0) //把这个P放去岸上
{
clickACharacter(characters[personOnBoat[0]]);
}
}
else if (personOnBoat[0] >= 0 && personOnBoat[0] <= 2) //第一个是D
{
if (next[1] > 0)
{
numDevilToBoat++;
}
else if (next[1] == 0)
{
clickACharacter(characters[personOnBoat[0]]);
}
}
if (personOnBoat[1] >= 3 && personOnBoat[1] <= 6) //第二个是P
{
if (next[0] == 2 || (next[0] == 1 && numPriestToBoat == 0)) //P不用动
{
numPriestToBoat++;
}
else if (next[0] == 0 || (next[0] == 1 && numPriestToBoat == 1)) //把这个P放去岸上
{
clickACharacter(characters[personOnBoat[1]]);
}
}
else if (personOnBoat[1] >= 0 && personOnBoat[1] <= 2) //第二个是D
{
if (next[1] == 2 || (next[1] == 1 && numDevilToBoat == 0))
{
numDevilToBoat++;
}
else if (next[1] == 0 || (next[1] == 1 && numDevilToBoat == 1))
{
clickACharacter(characters[personOnBoat[1]]);
}
}
/*
* 岸 -> 船
*/
for (int i = 0; i < next[0] - numPriestToBoat; i++) // P
{
int index = -1;
if (boatPos == 1)
{
index = leftBank.getAPriestIndex();
}
else if (boatPos == 2)
{
index = rightBank.getAPriestIndex();
}
clickACharacter(characters[index]);
}
for (int i = 0; i < next[1] - numDevilToBoat; i++) // P
{
int index = -1;
if (boatPos == 1)
{
index = leftBank.getADevilIndex();
}
else if (boatPos == 2)
{
index = rightBank.getADevilIndex();
}
clickACharacter(characters[index]);
}
//移动船
Invoke("moveBoat", (float)0.6);
}
public void NextActionAI()
{
//保证游戏状态是游戏中
int flag = judge.check();
if (flag == 1 || flag == 2)
{
return;
}
//得到当前状态
//计算所有在左边的牧师/恶魔
int numDevilLeft = judge.from_devil, numPriestLeft = judge.from_priest;
Debug.Log("numDevilLeft " + numDevilLeft);
Debug.Log("numPriestLeft " + numPriestLeft);
int boatPos = judge.Boat.get_is_from();
//获取下一个状态
Debug.Log("State:" + numDevilLeft + numPriestLeft + judge.Boat.get_is_from());
int[] next = ai.getNextAction(numDevilLeft, numPriestLeft, judge.Boat.get_is_from());
Debug.Log("next[0] " + next[0]);
Debug.Log("next[1] " + next[1]);
//其实next就表示要放在船上的人
//转换到下一个状态
/*
* numDveilToBoat = 0, numPriestToBoat = 0 要变得和next一样
* 先boat -> 岸
* 第一个是P
* next[0] > 0 留着 numPriestToBoat++
* next[0] = 0 放回去
* 第一个是D
* next[1] 同上 numDveilToBoat++
* 第二个是P
* next[0] = 2 且 numPriestToBoat = 1 留着
* next[0] = 1 放回去
* 第二个是D
* 同上
* 再 岸 -> boat
* 看一下 num和next没满足的，放岸上的去船上即可
*/
int numPriestToBoat = 0, numDevilToBoat = 0;
int[] personOnBoat = judge.Boat.getPersonOnBoat();
Debug.Log("******************Boat0 " + personOnBoat[0] + "*******************boat1" + personOnBoat[1]);
if (personOnBoat[0] >= 3 && personOnBoat[0] <= 6) //第一个是P
{
if (next[0] > 0) //P保持不动
{
numPriestToBoat++;
}
else if (next[0] == 0) //把这个P放去岸上
{
Debug.Log("**********************************getoff P" + personOnBoat[0]);
moveCharacter(characters[personOnBoat[0]]);
}
}
else if (personOnBoat[0] >= 0 && personOnBoat[0] <= 2) //第一个是D
{
if (next[1] > 0)
{
numDevilToBoat++;
}
else if (next[1] == 0)
{
Debug.Log("**********************************getoff D" + personOnBoat[0]);
moveCharacter(characters[personOnBoat[0]]);
}
}
if (personOnBoat[1] >= 3 && personOnBoat[1] <= 6) //第二个是P
{
if (next[0] == 2 || (next[0] == 1 && numPriestToBoat == 0)) //P不用动
{
numPriestToBoat++;
}
else if (next[0] == 0 || (next[0] == 1 && numPriestToBoat == 1)) //把这个P放去岸上
{
Debug.Log("**********************************getoff P" + personOnBoat[1]);
moveCharacter(characters[personOnBoat[1]]);
}
}
else if (personOnBoat[1] >= 0 && personOnBoat[1] <= 2) //第二个是D
{
if (next[1] == 2 || (next[1] == 1 && numDevilToBoat == 0))
{
numDevilToBoat++;
}
else if (next[1] == 0 || (next[1] == 1 && numDevilToBoat == 1))
{
Debug.Log("**********************************getoff D" + personOnBoat[1]);
moveCharacter(characters[personOnBoat[1]]);
}
}
/*
* 岸 -> 船
*/
for (int i = 0; i < next[0] - numPriestToBoat; i++) // P
{
int index = -1;
if (boatPos == 1)
{
index = fromCoast.getAPriestIndex();
}
else if (boatPos == -1)
{
index = toCoast.getAPriestIndex();
}
Debug.Log("**********************************geton P" + index);
moveCharacter(characters[index]);
}
for (int i = 0; i < next[1] - numDevilToBoat; i++) // D
{
int index = -1;
if (boatPos == 1)
{
index = fromCoast.getADevilIndex();
}
else if (boatPos == -1)
{
index = toCoast.getADevilIndex();
}
Debug.Log("**********************************geton D" + index);
moveCharacter(characters[index]);
}
//移动船
Invoke("moveBoat", (float)0.6);
Debug.Log("------------------------------------------------------");
}