public individual(individual old)
{
this.path = new int[old.path.Length];
for (int x = 0; x < old.path.Length; x++)
{
this.path[x] = old.path[x];
}
this.cost = old.cost;
}
public void solve(ref City[] Cities, int maxTime, ref string timeOut, ref int bssfUpdates, ref ProblemAndSolver.TSPSolution bssf, ref double bssfCost)
{
Stopwatch timer = new Stopwatch();
timer.Start();
// At the very least, stop when you run out of time
while (timer.ElapsedMilliseconds < maxTime)
{
init(Cities);
// Pick two parents
int indexA = parentSelection(-1, Cities.Length);
int[] parentA = species[indexA].path;
int[] parentB = species[parentSelection(indexA, Cities.Length)].path;
// Have them reproduce
individual child = new individual();
child.path = reproduce(ref parentA, ref parentB, Cities.Length);
child.cost = determineFitness(ref Cities, child.path);
// Store the child somewhere
// TODO - DO SOMETHING COOL
// for now just store at least cost guy. If none, don't keep
for (int i = 0; i < Cities.Length; i++)
{
if (species[i].cost > child.cost)
{
species[i] = new individual(child);
bssfUpdates++;
break;
}
}
}
// Find out the best
int best = 0;
for (int i = 1; i < Cities.Length; i++)
{
if (species[i].cost < species[best].cost)
{
best = i;
}
}
ArrayList Route = new ArrayList();
Route.Clear();
for (int i = 0; i < species[best].path.Length; i++)
{
Route.Add(Cities[species[best].path[i]]);
}
bssf = new ProblemAndSolver.TSPSolution(Route);
bssfCost = bssf.costOfRoute();
// Return variables
timer.Stop();
timeOut = timer.Elapsed.ToString();
}