示例#1
0
 // Apply mask penalty rule 3 and return the penalty. Find consecutive cells of 00001011101 or
 // 10111010000, and give penalty to them.  If we find patterns like 000010111010000, we give
 // penalties twice (i.e. 40 * 2).
 public static int applyMaskPenaltyRule3(ByteMatrix matrix)
 {
     int penalty = 0;
     sbyte[][] array = matrix.getArray();
     int width = matrix.width();
     int height = matrix.height();
     for (int y = 0; y < height; ++y)
     {
         for (int x = 0; x < width; ++x)
         {
             // Tried to simplify following conditions but failed.
             if (x + 6 < width &&
                 array[y][x] == 1 &&
                 array[y][x + 1] == 0 &&
                 array[y][x + 2] == 1 &&
                 array[y][x + 3] == 1 &&
                 array[y][x + 4] == 1 &&
                 array[y][x + 5] == 0 &&
                 array[y][x + 6] == 1 &&
                 ((x + 10 < width &&
                     array[y][x + 7] == 0 &&
                     array[y][x + 8] == 0 &&
                     array[y][x + 9] == 0 &&
                     array[y][x + 10] == 0) ||
                     (x - 4 >= 0 &&
                         array[y][x - 1] == 0 &&
                         array[y][x - 2] == 0 &&
                         array[y][x - 3] == 0 &&
                         array[y][x - 4] == 0)))
             {
                 penalty += 40;
             }
             if (y + 6 < height &&
                 array[y][x] == 1 &&
                 array[y + 1][x] == 0 &&
                 array[y + 2][x] == 1 &&
                 array[y + 3][x] == 1 &&
                 array[y + 4][x] == 1 &&
                 array[y + 5][x] == 0 &&
                 array[y + 6][x] == 1 &&
                 ((y + 10 < height &&
                     array[y + 7][x] == 0 &&
                     array[y + 8][x] == 0 &&
                     array[y + 9][x] == 0 &&
                     array[y + 10][x] == 0) ||
                     (y - 4 >= 0 &&
                         array[y - 1][x] == 0 &&
                         array[y - 2][x] == 0 &&
                         array[y - 3][x] == 0 &&
                         array[y - 4][x] == 0)))
             {
                 penalty += 40;
             }
         }
     }
     return penalty;
 }
示例#2
0
 // Apply mask penalty rule 2 and return the penalty. Find 2x2 blocks with the same color and give
 // penalty to them.
 public static int applyMaskPenaltyRule2(ByteMatrix matrix)
 {
     int penalty = 0;
     sbyte[][] array = matrix.getArray();
     int width = matrix.width();
     int height = matrix.height();
     for (int y = 0; y < height - 1; ++y)
     {
         for (int x = 0; x < width - 1; ++x)
         {
             int value = array[y][x];
             if (value == array[y][x + 1] && value == array[y + 1][x] && value == array[y + 1][x + 1])
             {
                 penalty += 3;
             }
         }
     }
     return penalty;
 }
        // Note that the input matrix uses 0 == white, 1 == black, while the output matrix uses
        // 0 == black, 255 == white (i.e. an 8 bit greyscale bitmap).
        private static ByteMatrix renderResult(QRCode code, int width, int height)
        {
            ByteMatrix input = code.getMatrix();
            int inputWidth = input.width();
            int inputHeight = input.height();
            int qrWidth = inputWidth + (QUIET_ZONE_SIZE << 1);
            int qrHeight = inputHeight + (QUIET_ZONE_SIZE << 1);
            int outputWidth = Math.Max(width, qrWidth);
            int outputHeight = Math.Max(height, qrHeight);

            int multiple = Math.Min(outputWidth / qrWidth, outputHeight / qrHeight);
            // Padding includes both the quiet zone and the extra white pixels to accomodate the requested
            // dimensions. For example, if input is 25x25 the QR will be 33x33 including the quiet zone.
            // If the requested size is 200x160, the multiple will be 4, for a QR of 132x132. These will
            // handle all the padding from 100x100 (the actual QR) up to 200x160.
            int leftPadding = (outputWidth - (inputWidth * multiple)) / 2;
            int topPadding = (outputHeight - (inputHeight * multiple)) / 2;

            ByteMatrix output = new ByteMatrix(outputHeight, outputWidth);
            sbyte[][] outputArray = output.getArray();

            // We could be tricky and use the first row in each set of multiple as the temporary storage,
            // instead of allocating this separate array.
            sbyte[] row = new sbyte[outputWidth];

            // 1. Write the white lines at the top
            for (int y = 0; y < topPadding; y++) {
              setRowColor(outputArray[y], unchecked((sbyte)255));
            }

            // 2. Expand the QR image to the multiple
            sbyte[][] inputArray = input.getArray();
            for (int y = 0; y < inputHeight; y++) {
              // a. Write the white pixels at the left of each row
              for (int x = 0; x < leftPadding; x++) {
                row[x] = unchecked((sbyte) 255);
              }

              // b. Write the contents of this row of the barcode
              int offset = leftPadding;
              for (int x = 0; x < inputWidth; x++) {
                sbyte value = (inputArray[y][x] == 1) ? (sbyte) 0 : unchecked((sbyte) 255);
                for (int z = 0; z < multiple; z++) {
                  row[offset + z] = value;
                }
                offset += multiple;
              }

              // c. Write the white pixels at the right of each row
              offset = leftPadding + (inputWidth * multiple);
              for (int x = offset; x < outputWidth; x++) {
                row[x] = unchecked((sbyte) 255);
              }

              // d. Write the completed row multiple times
              offset = topPadding + (y * multiple);
              for (int z = 0; z < multiple; z++) {
                System.Array.Copy(row, 0, outputArray[offset + z], 0, outputWidth);
              }
            }

            // 3. Write the white lines at the bottom
            int offset2 = topPadding + (inputHeight * multiple);
            for (int y = offset2; y < outputHeight; y++)
            {
              setRowColor(outputArray[y], unchecked((sbyte) 255));
            }
            return output;
        }
示例#4
0
 // Helper function for applyMaskPenaltyRule1. We need this for doing this calculation in both
 // vertical and horizontal orders respectively.
 private static int applyMaskPenaltyRule1Internal(ByteMatrix matrix, bool isHorizontal)
 {
     int penalty = 0;
     int numSameBitCells = 0;
     int prevBit = -1;
     // Horizontal mode:
     //   for (int i = 0; i < matrix.height(); ++i) {
     //     for (int j = 0; j < matrix.width(); ++j) {
     //       int bit = matrix.get(i, j);
     // Vertical mode:
     //   for (int i = 0; i < matrix.width(); ++i) {
     //     for (int j = 0; j < matrix.height(); ++j) {
     //       int bit = matrix.get(j, i);
     int iLimit = isHorizontal ? matrix.height() : matrix.width();
     int jLimit = isHorizontal ? matrix.width() : matrix.height();
     sbyte[][] array = matrix.getArray();
     for (int i = 0; i < iLimit; ++i)
     {
         for (int j = 0; j < jLimit; ++j)
         {
             int bit = isHorizontal ? array[i][j] : array[j][i];
             if (bit == prevBit)
             {
                 numSameBitCells += 1;
                 // Found five repetitive cells with the same color (bit).
                 // We'll give penalty of 3.
                 if (numSameBitCells == 5)
                 {
                     penalty += 3;
                 }
                 else if (numSameBitCells > 5)
                 {
                     // After five repetitive cells, we'll add the penalty one
                     // by one.
                     penalty += 1;
                 }
             }
             else
             {
                 numSameBitCells = 1;  // Include the cell itself.
                 prevBit = bit;
             }
         }
         numSameBitCells = 0;  // Clear at each row/column.
     }
     return penalty;
 }
示例#5
0
 // Apply mask penalty rule 4 and return the penalty. Calculate the ratio of dark cells and give
 // penalty if the ratio is far from 50%. It gives 10 penalty for 5% distance. Examples:
 // -   0% => 100
 // -  40% =>  20
 // -  45% =>  10
 // -  50% =>   0
 // -  55% =>  10
 // -  55% =>  20
 // - 100% => 100
 public static int applyMaskPenaltyRule4(ByteMatrix matrix)
 {
     int numDarkCells = 0;
     sbyte[][] array = matrix.getArray();
     int width = matrix.width();
     int height = matrix.height();
     for (int y = 0; y < height; ++y)
     {
         for (int x = 0; x < width; ++x)
         {
             if (array[y][x] == 1)
             {
                 numDarkCells += 1;
             }
         }
     }
     int numTotalCells = matrix.height() * matrix.width();
     double darkRatio = (double)numDarkCells / numTotalCells;
     return Math.Abs((int)(darkRatio * 100 - 50)) / 5 * 10;
 }