public static IEnumerable <DataAttribute> create_memento
(time.ClockTime clock_time)
{
return(new DataAttribute[] {
DataAttribute.create_value("seconds_from_midnight", clock_time.seconds_from_midnight.ToString())
});
}
public static IEnumerable <DataAttribute> create_memento
(domain.DiaryEntry diary_entry)
{
return(new DataAttribute[] {
DataAttribute.create_collection("start_time", time.serialisation.ClockTime.create_memento(diary_entry.start_time))
});
}
public static IEnumerable <DataAttribute> create_memento
(domain.Day day)
{
return(new DataAttribute[] {
DataAttribute.create_value("summary", day.summary),
DataAttribute.create_collection("date", time.serialisation.Date.create_attribute_memento(day.date)),
DataAttribute.create_collection("diary", day.diary.Select((de, i) => DataAttribute.create_collection(i.ToString(), DiaryEntry.create_memento(de))))
});
}
// Q. Why do return types not count as part of a method signatiure?
public static IEnumerable <DataAttribute> create_attribute_memento
(time.Date date)
{
return(new[] {
DataAttribute.create_value("year", date.year.ToString())
, DataAttribute.create_value("month", date.month.ToString())
, DataAttribute.create_value("day", date.day.ToString())
});
}
