示例#1
0
文件: Matrix3.cs 项目: tcoats/Voodoo
 public Matrix4 ConvertToW()
 {
     Matrix4 result = new Matrix4();
     for (int i = 0; i < 3; i++)
         for (int j = 0; j < 3; j++)
             result[i, j] = entry[Matrix4.I(i, j)];
     // magical W value
     result.entry[15] = 1;
     return result;
 }
示例#2
0
文件: Vector4.cs 项目: tcoats/Voodoo
 public Vector4 Mult(Matrix4 matrix)
 {
     return new Vector4(
             tuple[0] * matrix.entry[ 0] + tuple[1] * matrix.entry[ 1]
           + tuple[2] * matrix.entry[ 2] + tuple[3] * matrix.entry[ 3],
             tuple[0] * matrix.entry[ 4] + tuple[1] * matrix.entry[ 5]
           + tuple[2] * matrix.entry[ 6] + tuple[3] * matrix.entry[ 7],
             tuple[0] * matrix.entry[ 8] + tuple[1] * matrix.entry[ 9]
           + tuple[2] * matrix.entry[10] + tuple[3] * matrix.entry[11],
             tuple[0] * matrix.entry[12] + tuple[1] * matrix.entry[13]
           + tuple[2] * matrix.entry[14] + tuple[3] * matrix.entry[15]);
 }
示例#3
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Transpose()
 {
     Matrix4 result = new Matrix4();
     for (int i = 0; i < 4; i++)
         for (int j = 0; j < 4; j++)
             result.entry[I(i, j)] += entry[I(j, i)];
     return result;
 }
示例#4
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 TransposeTimes(Matrix4 matrix)
 {
     // P = A^T*B, P[r][c] = sum_m A[m][r]*B[m][c]
     Matrix4 result = new Matrix4();
     for (int row = 0; row < 4; row++)
     {
         for (int col = 0; col < 4; col++)
         {
             int i = I(row, col);
             result.entry[i] = 0;
             for (int mid = 0; mid < 4; mid++)
                 result.entry[i] += entry[I(mid, row)] * matrix.entry[I(mid, col)];
         }
     }
     return result;
 }
示例#5
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Negative()
 {
     Matrix4 result = new Matrix4();
     for (int i = 0; i < 16; i++)
         result.entry[i] = -entry[i];
     return result;
 }
示例#6
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Sub(Matrix4 matrix)
 {
     Matrix4 result = new Matrix4();
     for (int i = 0; i < 16; i++)
         result.entry[i] = entry[i] - matrix.entry[i];
     return result;
 }
示例#7
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Mult(double scalar)
 {
     Matrix4 result = new Matrix4();
     for (int i = 0; i < 16; i++)
         result.entry[i] = entry[i] * scalar;
     return result;
 }
示例#8
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Mult(Matrix4 matrix)
 {
     Matrix4 result = new Matrix4();
     for (int row = 0; row < 4; row++)
     {
         for (int col = 0; col < 4; col++)
         {
             int i = I(row, col);
             result.entry[i] = 0;
             for (int mid = 0; mid < 4; mid++)
                 result.entry[i] += entry[I(row, mid)] * matrix.entry[I(mid, col)];
         }
     }
     return result;
 }
示例#9
0
文件: Matrix4.cs 项目: tcoats/Voodoo
        public Matrix4 Inverse()
        {
            double a0 = entry[ 0] * entry[ 5] - entry[ 1] * entry[ 4];
            double a1 = entry[ 0] * entry[ 6] - entry[ 2] * entry[ 4];
            double a2 = entry[ 0] * entry[ 7] - entry[ 3] * entry[ 4];
            double a3 = entry[ 1] * entry[ 6] - entry[ 2] * entry[ 5];
            double a4 = entry[ 1] * entry[ 7] - entry[ 3] * entry[ 5];
            double a5 = entry[ 2] * entry[ 7] - entry[ 3] * entry[ 6];
            double b0 = entry[ 8] * entry[13] - entry[ 9] * entry[12];
            double b1 = entry[ 8] * entry[14] - entry[10] * entry[12];
            double b2 = entry[ 8] * entry[15] - entry[11] * entry[12];
            double b3 = entry[ 9] * entry[14] - entry[10] * entry[13];
            double b4 = entry[ 9] * entry[15] - entry[11] * entry[13];
            double b5 = entry[10] * entry[15] - entry[11] * entry[14];

            double det = a0 * b5 - a1 * b4 + a2 * b3 + a3 * b2 - a4 * b1 + a5 * b0;

            if (det <= 0)
                return Matrix4.Zero;

            Matrix4 result = new Matrix4();

            result.entry[ 0] = + entry[ 5] * b5 - entry[ 6] * b4 + entry[ 7] * b3;
            result.entry[ 4] = - entry[ 4] * b5 + entry[ 6] * b2 - entry[ 7] * b1;
            result.entry[ 8] = + entry[ 4] * b4 - entry[ 5] * b2 + entry[ 7] * b0;
            result.entry[12] = - entry[ 4] * b3 + entry[ 5] * b1 - entry[ 6] * b0;
            result.entry[ 1] = - entry[ 1] * b5 + entry[ 2] * b4 - entry[ 3] * b3;
            result.entry[ 5] = + entry[ 0] * b5 - entry[ 2] * b2 + entry[ 3] * b1;
            result.entry[ 9] = - entry[ 0] * b4 + entry[ 1] * b2 - entry[ 3] * b0;
            result.entry[13] = + entry[ 0] * b3 - entry[ 1] * b1 + entry[ 2] * b0;
            result.entry[ 2] = + entry[13] * a5 - entry[14] * a4 + entry[15] * a3;
            result.entry[ 6] = - entry[12] * a5 + entry[14] * a2 - entry[15] * a1;
            result.entry[10] = + entry[12] * a4 - entry[13] * a2 + entry[15] * a0;
            result.entry[14] = - entry[12] * a3 + entry[13] * a1 - entry[14] * a0;
            result.entry[ 3] = - entry[ 9] * a5 + entry[10] * a4 - entry[11] * a3;
            result.entry[ 7] = + entry[ 8] * a5 - entry[10] * a2 + entry[11] * a1;
            result.entry[11] = - entry[ 8] * a4 + entry[ 9] * a2 - entry[11] * a0;
            result.entry[15] = + entry[ 8] * a3 - entry[ 9] * a1 + entry[10] * a0;

            double invDet = 1 / det;
            for (int i = 0; i < 4; i++)
                for (int j = 0; j < 4; j++)
                    result[i, j] *= invDet;

            return result;
        }
示例#10
0
文件: Matrix4.cs 项目: tcoats/Voodoo
 public Matrix4 Div(double scalar)
 {
     Matrix4 result = new Matrix4();
     if (scalar != 0)
     {
         double invScalar = 1 / scalar;
         for (int i = 0; i < 16; i++)
             result.entry[i] = entry[i] * invScalar;;
     }
     else
         for (int i = 0; i < 16; i++)
             result.entry[i] = double.MaxValue;
     return result;
 }
示例#11
0
文件: Matrix4.cs 项目: tcoats/Voodoo
        public Matrix4 Adjoint()
        {
            double a0 = entry[ 0] * entry[ 5] - entry[ 1] * entry[ 4];
            double a1 = entry[ 0] * entry[ 6] - entry[ 2] * entry[ 4];
            double a2 = entry[ 0] * entry[ 7] - entry[ 3] * entry[ 4];
            double a3 = entry[ 1] * entry[ 6] - entry[ 2] * entry[ 5];
            double a4 = entry[ 1] * entry[ 7] - entry[ 3] * entry[ 5];
            double a5 = entry[ 2] * entry[ 7] - entry[ 3] * entry[ 6];
            double b0 = entry[ 8] * entry[13] - entry[ 9] * entry[12];
            double b1 = entry[ 8] * entry[14] - entry[10] * entry[12];
            double b2 = entry[ 8] * entry[15] - entry[11] * entry[12];
            double b3 = entry[ 9] * entry[14] - entry[10] * entry[13];
            double b4 = entry[ 9] * entry[15] - entry[11] * entry[13];
            double b5 = entry[10] * entry[15] - entry[11] * entry[14];

            Matrix4 result = new Matrix4();

            result.entry[ 0] = + entry[ 5] * b5 - entry[ 6] * b4 + entry[ 7] * b3;
            result.entry[ 4] = - entry[ 4] * b5 + entry[ 6] * b2 - entry[ 7] * b1;
            result.entry[ 8] = + entry[ 4] * b4 - entry[ 5] * b2 + entry[ 7] * b0;
            result.entry[12] = - entry[ 4] * b3 + entry[ 5] * b1 - entry[ 6] * b0;
            result.entry[ 1] = - entry[ 1] * b5 + entry[ 2] * b4 - entry[ 3] * b3;
            result.entry[ 5] = + entry[ 0] * b5 - entry[ 2] * b2 + entry[ 3] * b1;
            result.entry[ 9] = - entry[ 0] * b4 + entry[ 1] * b2 - entry[ 3] * b0;
            result.entry[13] = + entry[ 0] * b3 - entry[ 1] * b1 + entry[ 2] * b0;
            result.entry[ 2] = + entry[13] * a5 - entry[14] * a4 + entry[15] * a3;
            result.entry[ 6] = - entry[12] * a5 + entry[14] * a2 - entry[15] * a1;
            result.entry[10] = + entry[12] * a4 - entry[13] * a2 + entry[15] * a0;
            result.entry[14] = - entry[12] * a3 + entry[13] * a1 - entry[14] * a0;
            result.entry[ 3] = - entry[ 9] * a5 + entry[10] * a4 - entry[11] * a3;
            result.entry[ 7] = + entry[ 8] * a5 - entry[10] * a2 + entry[11] * a1;
            result.entry[11] = - entry[ 8] * a4 + entry[ 9] * a2 - entry[11] * a0;
            result.entry[15] = + entry[ 8] * a3 - entry[ 9] * a1 + entry[10] * a0;

            return result;
        }