C# (CSharp) Test_ScintillaNET_Bug_01 Dialog.ShowDialog示例

示例#1

文件： Form1.cs 项目： labeuze/source

 private void OpenDialog()
 {
     Dialog dialog = new Dialog();
     // problem with ShowDialog()
     //dialog.ShowDialog();
     // problem with ShowDialog(this)
     dialog.ShowDialog(this);
     // no problem with Show()
     //dialog.Show();
 }

示例#2

文件： Form1.cs 项目： 24/source_04

        private void OpenDialog()
        {
            Dialog dialog = new Dialog();

            // problem with ShowDialog()
            //dialog.ShowDialog();
            // problem with ShowDialog(this)
            dialog.ShowDialog(this);
            // no problem with Show()
            //dialog.Show();
        }

示例#3

文件： Form1.cs 项目： labeuze/source

 private void OpenDialogInvoke()
 {
     if (InvokeRequired)
     {
         Invoke((Action)OpenDialogInvoke);
     }
     else
     {
         Dialog dialog = new Dialog();
         // problem with ShowDialog()
         //dialog.ShowDialog();
         // problem with ShowDialog(this)
         dialog.ShowDialog(this);
         // no problem with Show()
         //dialog.Show();
     }
 }

示例#4

文件： Form1.cs 项目： 24/source_04

 private void OpenDialogInvoke()
 {
     if (InvokeRequired)
     {
         Invoke((Action)OpenDialogInvoke);
     }
     else
     {
         Dialog dialog = new Dialog();
         // problem with ShowDialog()
         //dialog.ShowDialog();
         // problem with ShowDialog(this)
         dialog.ShowDialog(this);
         // no problem with Show()
         //dialog.Show();
     }
 }

示例#5

文件： Form2.cs 项目： labeuze/source

 private void OpenDialog()
 {
     Dialog dialog = new Dialog();
     dialog.ShowDialog();
 }

示例#6

        private void OpenDialog()
        {
            Dialog dialog = new Dialog();

            dialog.ShowDialog();
        }