/// probe() takes a position object as input, computes a Entry object, and returns /// a pointer to it. The result is also stored in a hash table, so we don't have /// to recompute everything when the same pawn structure occurs again. public static Pawns.Entry probe(Position pos, Pawns.Table entries) { Key key = pos.pawn_key(); Pawns.Entry e = entries[key]; if (e.key == key) { return(e); } e.key = key; e.value = evaluate(pos, e, ColorS.WHITE) - evaluate(pos, e, ColorS.BLACK); return(e); }
public static Score evaluate(Position pos, Pawns.Entry e, Color Us) { Color Them = (Us == ColorS.WHITE ? ColorS.BLACK : ColorS.WHITE); Square Up = (Us == ColorS.WHITE ? SquareS.DELTA_N : SquareS.DELTA_S); Square Right = (Us == ColorS.WHITE ? SquareS.DELTA_NE : SquareS.DELTA_SW); Square Left = (Us == ColorS.WHITE ? SquareS.DELTA_NW : SquareS.DELTA_SE); Bitboard b, p, doubled; Square s; File f; Rank r; bool passed, isolated, opposed, connected, backward, candidate, unsupported; Score value = ScoreS.SCORE_ZERO; Square[] pl = pos.list(Us, PieceTypeS.PAWN); int plPos = 0; Bitboard ourPawns = pos.pieces_color_piecetype(Us, PieceTypeS.PAWN); Bitboard theirPawns = pos.pieces_color_piecetype(Them, PieceTypeS.PAWN); e.passedPawns[Us] = e.candidatePawns[Us] = 0; e.kingSquares[Us] = SquareS.SQ_NONE; e.semiopenFiles[Us] = 0xFF; e.pawnAttacks[Us] = BitBoard.shift_bb(ourPawns, Right) | BitBoard.shift_bb(ourPawns, Left); e.pawnsOnSquares[Us][ColorS.BLACK] = Bitcount.popcount_Max15(ourPawns & BitBoard.DarkSquares); e.pawnsOnSquares[Us][ColorS.WHITE] = pos.count(Us, PieceTypeS.PAWN) - e.pawnsOnSquares[Us][ColorS.BLACK]; // Loop through all pawns of the current color and score each pawn while ((s = pl[plPos++]) != SquareS.SQ_NONE) { Debug.Assert(pos.piece_on(s) == Types.make_piece(Us, PieceTypeS.PAWN)); f = Types.file_of(s); // This file cannot be semi-open e.semiopenFiles[Us] &= ~(1 << f); // Previous rank p = BitBoard.rank_bb_square(s - Types.pawn_push(Us)); // Our rank plus previous one b = BitBoard.rank_bb_square(s) | p; // Flag the pawn as passed, isolated, doubled, // unsupported or connected (but not the backward one). connected = (ourPawns & BitBoard.adjacent_files_bb(f) & b) != 0; unsupported = (0 == (ourPawns & BitBoard.adjacent_files_bb(f) & p)); isolated = (0 == (ourPawns & BitBoard.adjacent_files_bb(f))); doubled = ourPawns & BitBoard.forward_bb(Us, s); opposed = (theirPawns & BitBoard.forward_bb(Us, s)) != 0; passed = (0 == (theirPawns & BitBoard.passed_pawn_mask(Us, s))); // Test for backward pawn. // If the pawn is passed, isolated, or connected it cannot be // backward. If there are friendly pawns behind on adjacent files // or if it can capture an enemy pawn it cannot be backward either. if ((passed | isolated | connected) || (ourPawns & BitBoard.pawn_attack_span(Them, s)) != 0 || (pos.attacks_from_pawn(s, Us) & theirPawns) != 0) { backward = false; } else { // We now know that there are no friendly pawns beside or behind this // pawn on adjacent files. We now check whether the pawn is // backward by looking in the forward direction on the adjacent // files, and picking the closest pawn there. b = BitBoard.pawn_attack_span(Us, s) & (ourPawns | theirPawns); b = BitBoard.pawn_attack_span(Us, s) & BitBoard.rank_bb_square(BitBoard.backmost_sq(Us, b)); // If we have an enemy pawn in the same or next rank, the pawn is // backward because it cannot advance without being captured. backward = ((b | BitBoard.shift_bb(b, Up)) & theirPawns) != 0; } Debug.Assert(opposed | passed | (BitBoard.pawn_attack_span(Us, s) & theirPawns) != 0); // A not-passed pawn is a candidate to become passed, if it is free to // advance and if the number of friendly pawns beside or behind this // pawn on adjacent files is higher than or equal to the number of // enemy pawns in the forward direction on the adjacent files. candidate = !(opposed | passed | backward | isolated) && (b = BitBoard.pawn_attack_span(Them, s + Types.pawn_push(Us)) & ourPawns) != 0 && Bitcount.popcount_Max15(b) >= Bitcount.popcount_Max15(BitBoard.pawn_attack_span(Us, s) & theirPawns); // Passed pawns will be properly scored in evaluation because we need // full attack info to evaluate passed pawns. Only the frontmost passed // pawn on each file is considered a true passed pawn. if (passed && 0 == doubled) { e.passedPawns[Us] |= BitBoard.SquareBB[s]; } // Score this pawn if (isolated) { value -= Isolated[opposed ? 1 : 0][f]; } if (unsupported && !isolated) { value -= UnsupportedPawnPenalty; } if (doubled != 0) { value -= Types.divScore(Doubled[f], BitBoard.rank_distance(s, BitBoard.lsb(doubled))); } if (backward) { value -= Backward[opposed ? 1 : 0][f]; } if (connected) { value += Connected[f][Types.relative_rank_square(Us, s)]; } if (candidate) { value += CandidatePassed[Types.relative_rank_square(Us, s)]; if (0 == doubled) { e.candidatePawns[Us] |= BitBoard.SquareBB[s]; } } } // In endgame it's better to have pawns on both wings. So give a bonus according // to file distance between left and right outermost pawns. if (pos.count(Us, PieceTypeS.PAWN) > 1) { b = (Bitboard)(e.semiopenFiles[Us] ^ 0xFF); value += PawnsFileSpan * (BitBoard.msb(b) - BitBoard.lsb(b)); } return(value); }