private int isBrecket(int wordNomber, ISentence sent, LongOperationAttribut attr)
{
string word = sent.get_Word(wordNomber).WordStr;
for (int i = 0; i < attr.attributSequence.Count; i++)
{
if (attr.attributSequence[i] is Brackets)
{
Brackets br = attr.attributSequence[i] as Brackets;
if ((br.atribut1.word == word) || (br.atribut2.word == word))
{
return(i);
}
for (int j = 0; j < br.unionsForAttr2.Count; j++)
{
if ((br.unionsForAttr2[j] as ElementaryAttribut).word == word)
{
return(i);
}
}
}
}
return(-1);
}
/// <summary>
/// Добавление атрибута с предпроверкой добавлять ли его в последовательность атрибутов или же уточнять брэкет
/// </summary>
/// <param name="word"></param>
/// <param name="notOperation"></param>
/// <param name="operetionBefore"></param>
/// <param name="wordNomber"></param>
/// <param name="sent"></param>
/// <param name="attr"></param>
public void addElementaryAttribut(string word, string notOperation, IWord inWord, string operetionBefore, int saverWordNomber, ISentence sent, LongOperationAttribut attr)
{
int brNo = isBrecket(saverWordNomber, sent, attr);
ElementaryAttribut attribut = new ElementaryAttribut(notOperation, word, inWord);
if (brNo != -1)
{
//уточнить брэкет
(attr.attributSequence[brNo] as Brackets).addUnionToAttr2(attribut, operetionBefore);
}
else
{
//просто добавляем новый элемент в последовательность
attributSequence.Add(attribut);
operators.Add(operetionBefore);
parentEp.getString();
}
}
