示例#1
0
        //***********************************************************************
        // Performs the calculation of the kth term in the Lucas Sequence.
        // For details of the algorithm, see reference [9].
        //
        // k must be odd.  i.e LSB == 1
        //***********************************************************************

        private static BigInteger[] LucasSequenceHelper(BigInteger P, BigInteger Q,
                                                        BigInteger k, BigInteger n,
                                                        BigInteger constant, int s)
        {
            var result = new BigInteger[3];

            if ((k.data[0] & 0x00000001) == 0)
                throw (new ArgumentException("Argument k must be odd."));

            int numbits = k.bitCount();
            uint mask = (uint) 0x1 << ((numbits & 0x1F) - 1);

            // v = v0, v1 = v1, u1 = u1, Q_k = Q^0

            BigInteger v = 2%n,
                       Q_k = 1%n,
                       v1 = P%n,
                       u1 = Q_k;
            bool flag = true;

            for (int i = k.dataLength - 1; i >= 0; i--) // iterate on the binary expansion of k
            {
                //Console.WriteLine("round");
                while (mask != 0)
                {
                    if (i == 0 && mask == 0x00000001) // last bit
                        break;

                    if ((k.data[i] & mask) != 0) // bit is set
                    {
                        // index doubling with addition

                        u1 = (u1*v1)%n;

                        v = ((v*v1) - (P*Q_k))%n;
                        v1 = n.BarrettReduction(v1*v1, n, constant);
                        v1 = (v1 - ((Q_k*Q) << 1))%n;

                        if (flag)
                            flag = false;
                        else
                            Q_k = n.BarrettReduction(Q_k*Q_k, n, constant);

                        Q_k = (Q_k*Q)%n;
                    }
                    else
                    {
                        // index doubling
                        u1 = ((u1*v) - Q_k)%n;

                        v1 = ((v*v1) - (P*Q_k))%n;
                        v = n.BarrettReduction(v*v, n, constant);
                        v = (v - (Q_k << 1))%n;

                        if (flag)
                        {
                            Q_k = Q%n;
                            flag = false;
                        }
                        else
                            Q_k = n.BarrettReduction(Q_k*Q_k, n, constant);
                    }

                    mask >>= 1;
                }
                mask = 0x80000000;
            }

            // at this point u1 = u(n+1) and v = v(n)
            // since the last bit always 1, we need to transform u1 to u(2n+1) and v to v(2n+1)

            u1 = ((u1*v) - Q_k)%n;
            v = ((v*v1) - (P*Q_k))%n;
            if (flag)
                flag = false;
            else
                Q_k = n.BarrettReduction(Q_k*Q_k, n, constant);

            Q_k = (Q_k*Q)%n;


            for (int i = 0; i < s; i++)
            {
                // index doubling
                u1 = (u1*v)%n;
                v = ((v*v) - (Q_k << 1))%n;

                if (flag)
                {
                    Q_k = Q%n;
                    flag = false;
                }
                else
                    Q_k = n.BarrettReduction(Q_k*Q_k, n, constant);
            }

            result[0] = u1;
            result[1] = v;
            result[2] = Q_k;

            return result;
        }
示例#2
0
        //***********************************************************************
        // Modulo Exponentiation
        //***********************************************************************

        public BigInteger ModPow(BigInteger exp, BigInteger n)
        {
            if ((exp.data[maxLength - 1] & 0x80000000) != 0)
                throw (new ArithmeticException("Positive exponents only."));

            BigInteger resultNum = 1;
            BigInteger tempNum;
            bool thisNegative = false;

            if ((this.data[maxLength - 1] & 0x80000000) != 0) // negative this
            {
                tempNum = -this%n;
                thisNegative = true;
            }
            else
                tempNum = this%n; // ensures (tempNum * tempNum) < b^(2k)

            if ((n.data[maxLength - 1] & 0x80000000) != 0) // negative n
                n = -n;

            // calculate constant = b^(2k) / m
            var constant = new BigInteger();

            int i = n.dataLength << 1;
            constant.data[i] = 0x00000001;
            constant.dataLength = i + 1;

            constant = constant/n;
            int totalBits = exp.bitCount();
            int count = 0;

            // perform squaring and multiply exponentiation
            for (int pos = 0; pos < exp.dataLength; pos++)
            {
                uint mask = 0x01;
                //Console.WriteLine("pos = " + pos);

                for (int index = 0; index < 32; index++)
                {
                    if ((exp.data[pos] & mask) != 0)
                        resultNum = this.BarrettReduction(resultNum*tempNum, n, constant);

                    mask <<= 1;

                    tempNum = this.BarrettReduction(tempNum*tempNum, n, constant);


                    if (tempNum.dataLength == 1 && tempNum.data[0] == 1)
                    {
                        if (thisNegative && (exp.data[0] & 0x1) != 0) //odd exp
                            return -resultNum;
                        return resultNum;
                    }
                    count++;
                    if (count == totalBits)
                        break;
                }
            }

            if (thisNegative && (exp.data[0] & 0x1) != 0) //odd exp
                return -resultNum;

            return resultNum;
        }