示例#1
0
 /// <summary>
 ///  check that algorithm computes either the topological order or finds a directed cycle
 /// </summary>
 /// <param name="G"></param>
 /// <param name="v"></param>
 private void dfs(Digraph G, int v)
 {
     onStack[v] = true;
     marked[v]  = true;
     foreach (int w in G.Adj(v))
     {
         //short circuit if directed cycle found
         if (cycle != null)
         {
             return;
         }
         else if (!marked[w])
         {
             edgeTo[w] = v;
             dfs(G, w);
         }
         //trace back directed cycle
         else if (onStack[w])
         {
             cycle = new Stack <int>();
             for (int x = v; x != w; x = edgeTo[x])
             {
                 cycle.Push(x);
             }
             cycle.Push(w);
             cycle.Push(v);
         }
     }
     onStack[v] = false;
 }
示例#2
0
        /// <summary>
        /// bfs from single source
        /// </summary>
        /// <param name="g"></param>
        /// <param name="s"></param>
        private void bfs(Digraph g, int s)
        {
            Queue <int> q = new Queue <int>();

            for (int i = 0; i < g.V; i++)
            {
                distTo[i] = INFINITY;
            }

            //we can reach s
            distTo[s] = 0;
            marked[s] = true;
            q.Enqueue(s);

            while (q.Count > 0)
            {
                int v = q.Dequeue();
                foreach (int w in g.Adj(v))
                {
                    if (!marked[w])
                    {
                        edgeTo[w] = v;
                        distTo[w] = distTo[v] + 1;
                        marked[w] = true;
                        q.Enqueue(w);
                    }
                }
            }
        }
示例#3
0
        /// <summary>
        /// bfs from multi sources
        /// </summary>
        /// <param name="g"></param>
        /// <param name="sources"></param>
        private void bfs(Digraph g, IEnumerable <int> sources)
        {
            Queue <int> q = new Queue <int>();

            foreach (int s in sources)
            {
                marked[s] = true;
                distTo[s] = 0;
                q.Enqueue(s);
            }

            while (q.Count > 0)
            {
                int v = q.Dequeue();
                foreach (int w in g.Adj(v))
                {
                    if (!marked[w])
                    {
                        edgeTo[w] = v;
                        distTo[w] = distTo[v] + 1;
                        marked[w] = true;
                        q.Enqueue(w);
                    }
                }
            }
        }
 private void dfs(Digraph g, int v)
 {
     marked[v] = true;
     foreach (int w in g.Adj(v))
     {
         if (!marked[w])
         {
             dfs(g, w);
         }
     }
 }
 /// <summary>
 /// depth first search
 /// </summary>
 /// <param name="g"></param>
 /// <param name="v"></param>
 private void dfs(Digraph g, int v)
 {
     //before this run, marked[v] always false
     marked[v] = true;
     count++;
     connected.Add(v);
     foreach (int w in g.Adj(v))
     {
         if (!marked[w])
         {
             edgeTo[w] = v;
             dfs(g, w);
         }
     }
 }
示例#6
0
        /// <summary>
        /// run DFS in digraph G from vertex v and compute preorder/postorder
        /// </summary>
        /// <param name="g"></param>
        /// <param name="v"></param>
        private void dfs(Digraph g, int v)
        {
            if (marked[v])
            {
                return;
            }
            marked[v] = true;
            pre[v]    = preCounter++;
            preorder.Enqueue(v);

            foreach (int w in g.Adj(v))
            {
                if (!marked[v])
                {
                    dfs(g, w);
                }
            }
            postorder.Enqueue(v);
            post[v] = postCounter++;
        }