示例#1
0
        /// <summary>
        /// Does the three way merge between a common base and two sequences.
        /// </summary>
        /// <param name="base">base the common base sequence</param>
        /// <param name="ours">ours the first sequence to be merged</param>
        /// <param name="theirs">theirs the second sequence to be merged</param>
        /// <returns>the resulting content</returns>
        public static MergeResult merge(Sequence @base, Sequence ours,
            Sequence theirs)
        {
            List<Sequence> sequences = new List<Sequence>(3);
            sequences.Add(@base);
            sequences.Add(ours);
            sequences.Add(theirs);
            MergeResult result = new MergeResult(sequences);
            EditList oursEdits = new MyersDiff(@base, ours).getEdits();
            IteratorBase<Edit> baseToOurs = oursEdits.iterator();
            EditList theirsEdits = new MyersDiff(@base, theirs).getEdits();
            IteratorBase<Edit> baseToTheirs = theirsEdits.iterator();
            int current = 0; // points to the next line (first line is 0) of base
            // which was not handled yet
            Edit oursEdit = nextEdit(baseToOurs);
            Edit theirsEdit = nextEdit(baseToTheirs);

            // iterate over all edits from base to ours and from base to theirs
            // leave the loop when there are no edits more for ours or for theirs
            // (or both)
            while (theirsEdit != END_EDIT || oursEdit != END_EDIT)
            {
                if (oursEdit.EndA <= theirsEdit.BeginA)
                {
                    // something was changed in ours not overlapping with any change
                    // from theirs. First add the common part in front of the edit
                    // then the edit.
                    if (current != oursEdit.BeginA)
                    {
                        result.add(0, current, oursEdit.BeginA,
                            MergeChunk.ConflictState.NO_CONFLICT);
                    }
                    result.add(1, oursEdit.BeginB, oursEdit.EndB,
                        MergeChunk.ConflictState.NO_CONFLICT);
                    current = oursEdit.EndA;
                    oursEdit = nextEdit(baseToOurs);
                }
                else if (theirsEdit.EndA <= oursEdit.BeginA)
                {
                    // something was changed in theirs not overlapping with any
                    // from ours. First add the common part in front of the edit
                    // then the edit.
                    if (current != theirsEdit.BeginA)
                    {
                        result.add(0, current, theirsEdit.BeginA,
                            MergeChunk.ConflictState.NO_CONFLICT);
                    }
                    result.add(2, theirsEdit.BeginB, theirsEdit.EndB,
                        MergeChunk.ConflictState.NO_CONFLICT);
                    current = theirsEdit.EndA;
                    theirsEdit = nextEdit(baseToTheirs);
                }
                else
                {
                    // here we found a real overlapping modification

                    // if there is a common part in front of the conflict add it
                    if (oursEdit.BeginA != current
                        && theirsEdit.BeginA != current)
                    {
                        result.add(0, current, Math.Min(oursEdit.BeginA,
                            theirsEdit.BeginA), MergeChunk.ConflictState.NO_CONFLICT);
                    }

                    // set some initial values for the ranges in A and B which we
                    // want to handle
                    int oursBeginB = oursEdit.BeginB;
                    int theirsBeginB = theirsEdit.BeginB;
                    // harmonize the start of the ranges in A and B
                    if (oursEdit.BeginA < theirsEdit.BeginA)
                    {
                        theirsBeginB -= theirsEdit.BeginA
                            - oursEdit.BeginA;
                    }
                    else
                    {
                        oursBeginB -= oursEdit.BeginA - theirsEdit.BeginA;
                    }

                    // combine edits:
                    // Maybe an Edit on one side corresponds to multiple Edits on
                    // the other side. Then we have to combine the Edits of the
                    // other side - so in the end we can merge together two single
                    // edits.
                    //
                    // It is important to notice that this combining will extend the
                    // ranges of our conflict always downwards (towards the end of
                    // the content). The starts of the conflicting ranges in ours
                    // and theirs are not touched here.
                    //
                    // This combining is an iterative process: after we have
                    // combined some edits we have to do the check again. The
                    // combined edits could now correspond to multiple edits on the
                    // other side.
                    //
                    // Example: when this combining algorithm works on the following
                    // edits
                    // oursEdits=((0-5,0-5),(6-8,6-8),(10-11,10-11)) and
                    // theirsEdits=((0-1,0-1),(2-3,2-3),(5-7,5-7))
                    // it will merge them into
                    // oursEdits=((0-8,0-8),(10-11,10-11)) and
                    // theirsEdits=((0-7,0-7))
                    //
                    // Since the only interesting thing to us is how in ours and
                    // theirs the end of the conflicting range is changing we let
                    // oursEdit and theirsEdit point to the last conflicting edit
                    Edit nextOursEdit = nextEdit(baseToOurs);
                    Edit nextTheirsEdit = nextEdit(baseToTheirs);
                    for (; ; )
                    {
                        if (oursEdit.EndA > nextTheirsEdit.BeginA)
                        {
                            theirsEdit = nextTheirsEdit;
                            nextTheirsEdit = nextEdit(baseToTheirs);
                        }
                        else if (theirsEdit.EndA > nextOursEdit.BeginA)
                        {
                            oursEdit = nextOursEdit;
                            nextOursEdit = nextEdit(baseToOurs);
                        }
                        else
                        {
                            break;
                        }
                    }

                    // harmonize the end of the ranges in A and B
                    int oursEndB = oursEdit.EndB;
                    int theirsEndB = theirsEdit.EndB;
                    if (oursEdit.EndA < theirsEdit.EndA)
                    {
                        oursEndB += theirsEdit.EndA - oursEdit.EndA;
                    }
                    else
                    {
                        theirsEndB += oursEdit.EndA - theirsEdit.EndA;
                    }

                    // Add the conflict
                    result.add(1, oursBeginB, oursEndB,
                        MergeChunk.ConflictState.FIRST_CONFLICTING_RANGE);
                    result.add(2, theirsBeginB, theirsEndB,
                        MergeChunk.ConflictState.NEXT_CONFLICTING_RANGE);

                    current = Math.Max(oursEdit.EndA, theirsEdit.EndA);
                    oursEdit = nextOursEdit;
                    theirsEdit = nextTheirsEdit;
                }
            }
            // maybe we have a common part behind the last edit: copy it to the
            // result
            if (current < @base.size())
            {
                result.add(0, current, @base.size(), MergeChunk.ConflictState.NO_CONFLICT);
            }
            return result;
        }
示例#2
0
 public void assertDiff(string a, string b, string edits)
 {
     MyersDiff diff = new MyersDiff(toCharArray(a), toCharArray(b));
     Assert.AreEqual(edits, toString(diff.getEdits()));
 }