/**
* 获取每个节点的运算结果，并检验除法
* 1)除数为0
* 2)不能整除
* 出现以上两种情况的话将该运算符转换成其他三种运算符
*
* @return result
*/
public String getResult()
{
if (hasChild())
{
switch (str)
{
case "+":
return((int.Parse(getLchild().getResult()) + int.Parse(getRchild().getResult())).ToString());
case "-":
return((int.Parse(getLchild().getResult()) - int.Parse(getRchild().getResult())).ToString());
case "*":
return((int.Parse(getLchild().getResult()) * int.Parse(getRchild().getResult())).ToString());
case "/":
if (getRchild().getResult().Equals("0"))
{
while (str.Equals("/"))
{
str = (Ran.getOperator().ToString());
}
return(this.getResult());
}
else if (int.Parse(getLchild().getResult()) % int.Parse(getRchild().getResult()) != 0)
{
while (str.Equals("/"))
{
str = (Ran.getOperator()).ToString();
}
return(this.getResult());
}
else
{
return((int.Parse(getLchild().getResult()) / int.Parse(getRchild().getResult())).ToString());
}
}
}
return(str);
}
/**
* 生成二叉树
*/
public void createBTree()
{
Tree lchild, rchild, lnode, rnode;
if (num == 1)
{
lchild = new Tree((Ran.getNumber(30)).ToString(), null, null);
rchild = new Tree((Ran.getNumber(40)).ToString(), null, null);
root = new Tree((Ran.getOperator()).ToString(), lchild, rchild);
}
else
{
int num1 = 0;
int n = getDeep() - 3;
bool[] place = Ran.getChildPlace(num);
root = new Tree((Ran.getOperator()).ToString(), null, null);
opeList.Add(root);
for (int i = 0; i < n; i++)
{
for (int j = 0; j < (int)Math.Pow(2, i); j++, num1++)
{
lchild = new Tree((Ran.getOperator()).ToString(), null, null);
rchild = new Tree((Ran.getOperator()).ToString(), null, null);
opeList[j + num1].setChild(lchild, rchild);
opeList.Add(lchild);
opeList.Add(rchild);
}
}
for (int i = 0; i < place.Length; i++)
{
if (place[i])
{
lnode = new Tree((Ran.getNumber(40)).ToString(), null, null);
rnode = new Tree((Ran.getNumber(60)).ToString(), null, null);
if (i % 2 == 0)
{
lchild = new Tree((Ran.getOperator()).ToString(), lnode, rnode);
opeList.Add(lchild);
opeList[num1].setLchild(lchild);
}
else
{
rchild = new Tree((Ran.getOperator()).ToString(), lnode, rnode);
opeList.Add(rchild);
opeList[num1].setRchild(rchild);
}
}
else
{
if (i % 2 == 0)
{
lchild = new Tree((Ran.getNumber(15)).ToString(), null, null);
opeList[num1].setLchild(lchild);
}
else
{
rchild = new Tree((Ran.getNumber(100)).ToString(), null, null);
opeList[num1].setRchild(rchild);
}
}
num1 = num1 + i % 2;
}
}
}
