示例#1
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 /// <summary>
 /// Set this based on the position vector and a rotation matrix.
 /// </summary>
 /// <param name="position"></param>
 /// <param name="R"></param>
 public void Initialize(B2Vec2 position, B2Mat22 rotation)
 {
 }
示例#2
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 /// <summary>
 /// Construct using a position vector and a rotation matrix.
 /// </summary>
 /// <param name="position"></param>
 /// <param name="R"></param>
 public B2Transform(B2Vec2 position, B2Mat22 rotation)
 {
 }
示例#3
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 /// <summary>
 /// Add this matrix.
 /// </summary>
 public void Add(B2Mat22 m)
 {
 }
示例#4
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 /// <summary>
 /// Solve A * x = b, where b is a column vector. This is more efficient
 /// than computing the inverse in one-shot cases.
 /// </summary>
 public B2Vec2 Solve(ref B2Mat22 mIn, float bX, float bY)
 {
     return null;
 }
示例#5
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 /// <summary>
 /// Set to this matrix.
 /// </summary>
 public void SetM(B2Mat22 m)
 {
 }
示例#6
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 /// <summary>
 /// Compute the inverse of this matrix, such that inv(A) * A = identity.
 /// </summary>
 public B2Mat22 GetInverse(ref B2Mat22 mIn)
 {
     return null;
 }