示例#1
0
        /// <summary>
        /// Computes the absolute value of a Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger whose absolute value is to be computed</param>
        /// <returns>The absolute value of the given BigInteger</returns>
        public static Base10BigInteger Abs(Base10BigInteger n)
        {
            Base10BigInteger res = new Base10BigInteger(n);

            res.sign = Sign.Positive;
            return(res);
        }
示例#2
0
        /// <summary>
        /// Adds two BigNumbers a and b, where a >= b, a, b non-negative.
        /// </summary>
        private static Base10BigInteger Add(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = new Base10BigInteger(a);
            long             trans = 0, temp;
            int i;

            for (i = 0; i < b.size; i++)
            {
                temp          = res.digits[i] + b.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans         = temp / NumberBase;
            }

            for (i = b.size; ((i < a.size) && (trans > 0)); i++)
            {
                temp          = res.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans         = temp / NumberBase;
            }

            if (trans > 0)
            {
                res.digits[res.size] = trans % NumberBase;
                res.size++;
                trans /= NumberBase;
            }

            return(res);
        }
示例#3
0
        /// <summary>
        /// Constructor creating a new Base10BigInteger as a copy of an existing Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger to be copied</param>
        public Base10BigInteger(Base10BigInteger n)
        {
            digits = new DigitContainer();
            size   = n.size;
            sign   = n.sign;

            for (int i = 0; i < n.size; i++)
            {
                digits[i] = n.digits[i];
            }
        }
示例#4
0
        /// <summary>
        /// Constructor creating a new Base10BigInteger as a copy of an existing Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger to be copied</param>
        public Base10BigInteger(Base10BigInteger n)
        {
            digits = new long[MaxSize];
            size   = n.size;
            sign   = n.sign;

            for (int i = 0; i < n.size; i++)
            {
                digits[i] = n.digits[i];
            }
        }
示例#5
0
        /// <summary>
        /// Subtracts the Base10BigInteger b from the Base10BigInteger a, where a >= b, a, b non-negative.
        /// </summary>
        private static Base10BigInteger Subtract(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = new Base10BigInteger(a);
            int  i;
            long temp, trans = 0;
            bool reducible = true;

            for (i = 0; i < b.size; i++)
            {
                temp = res.digits[i] - b.digits[i] - trans;
                if (temp < 0)
                {
                    trans = 1;
                    temp += NumberBase;
                }
                else
                {
                    trans = 0;
                }
                res.digits[i] = temp;
            }

            for (i = b.size; ((i < a.size) && (trans > 0)); i++)
            {
                temp = res.digits[i] - trans;
                if (temp < 0)
                {
                    trans = 1;
                    temp += NumberBase;
                }
                else
                {
                    trans = 0;
                }
                res.digits[i] = temp;
            }

            while ((res.size - 1 > 0) && (reducible == true))
            {
                if (res.digits[res.size - 1] == 0)
                {
                    res.size--;
                }
                else
                {
                    reducible = false;
                }
            }

            return(res);
        }
示例#6
0
        /// <summary>
        /// String representation of the current BigInteger, converted to its base-10 representation.
        /// </summary>
        /// <returns>The string representation of the current BigInteger</returns>
        public override string ToString()
        {
            Base10BigInteger res          = new Base10BigInteger();
            Base10BigInteger currentPower = new Base10BigInteger(1);

            for (int i = 0; i < size; i++)
            {
                res          += digits[i] * currentPower;
                currentPower *= NumberBase;
            }

            res.NumberSign = sign;

            return(res.ToString());
        }
示例#7
0
        /// <summary>
        /// Base10BigInteger inverse with respect to addition.
        /// </summary>
        /// <param name="n">The Base10BigInteger whose opposite is to be computed</param>
        /// <returns>The Base10BigInteger inverse with respect to addition</returns>
        public static Base10BigInteger Opposite(Base10BigInteger n)
        {
            Base10BigInteger res = new Base10BigInteger(n);

            if (res != Zero)
            {
                if (res.sign == Sign.Positive)
                {
                    res.sign = Sign.Negative;
                }
                else
                {
                    res.sign = Sign.Positive;
                }
            }

            return(res);
        }
示例#8
0
        /// <summary>
        /// Multiplies two Base10BigIntegers.
        /// </summary>
        private static Base10BigInteger Multiply(Base10BigInteger a, Base10BigInteger b)
        {
            int  i, j;
            long temp, trans = 0;

            Base10BigInteger res = new Base10BigInteger();

            res.size = a.size + b.size - 1;
            for (i = 0; i < res.size + 1; i++)
            {
                res.digits[i] = 0;
            }

            for (i = 0; i < a.size; i++)
            {
                if (a.digits[i] != 0)
                {
                    for (j = 0; j < b.size; j++)
                    {
                        if (b.digits[j] != 0)
                        {
                            res.digits[i + j] += a.digits[i] * b.digits[j];
                        }
                    }
                }
            }

            for (i = 0; i < res.size; i++)
            {
                temp          = res.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans         = temp / NumberBase;
            }

            if (trans > 0)
            {
                res.digits[res.size] = trans % NumberBase;
                res.size++;
                trans /= NumberBase;
            }

            return(res);
        }
示例#9
0
        /// <summary>
        /// Multiplication operation of two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>The Base10BigInteger result of the multiplication</returns>
        public static Base10BigInteger Multiplication(Base10BigInteger a, Base10BigInteger b)
        {
            if ((a == Zero) || (b == Zero))
            {
                return(Zero);
            }

            Base10BigInteger res = Multiply(Abs(a), Abs(b));

            if (a.sign == b.sign)
            {
                res.sign = Sign.Positive;
            }
            else
            {
                res.sign = Sign.Negative;
            }

            return(res);
        }
示例#10
0
        /// <summary>
        /// Determines whether the specified Base10BigInteger is equal to the current Base10BigInteger.
        /// </summary>
        /// <param name="other">The Base10BigInteger to compare with the current Base10BigInteger</param>
        /// <returns>True if the specified Base10BigInteger is equal to the current Base10BigInteger,
        /// false otherwise</returns>
        public bool Equals(Base10BigInteger other)
        {
            if (sign != other.sign)
            {
                return(false);
            }
            if (size != other.size)
            {
                return(false);
            }

            for (int i = 0; i < size; i++)
            {
                if (digits[i] != other.digits[i])
                {
                    return(false);
                }
            }

            return(true);
        }
示例#11
0
        /// <summary>
        /// Subtraction operation of two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>The Base10BigInteger result of the subtraction</returns>
        public static Base10BigInteger Subtraction(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = null;

            if ((a.sign == Sign.Positive) && (b.sign == Sign.Positive))
            {
                if (a >= b)
                {
                    res      = Subtract(a, b);
                    res.sign = Sign.Positive;
                }
                else
                {
                    res      = Subtract(b, a);
                    res.sign = Sign.Negative;
                }
            }

            if ((a.sign == Sign.Negative) && (b.sign == Sign.Negative))
            {
                if (a <= b)
                {
                    res      = Subtract(-a, -b);
                    res.sign = Sign.Negative;
                }
                else
                {
                    res      = Subtract(-b, -a);
                    res.sign = Sign.Positive;
                }
            }

            if ((a.sign == Sign.Positive) && (b.sign == Sign.Negative))
            {
                if (a >= (-b))
                {
                    res = Add(a, -b);
                }
                else
                {
                    res = Add(-b, a);
                }

                res.sign = Sign.Positive;
            }

            if ((a.sign == Sign.Negative) && (b.sign == Sign.Positive))
            {
                if ((-a) >= b)
                {
                    res = Add(-a, b);
                }
                else
                {
                    res = Add(b, -a);
                }

                res.sign = Sign.Negative;
            }

            return(res);
        }
示例#12
0
        /// <summary>
        /// Greater test between two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>True if a &gt; b, false otherwise</returns>
        public static bool Greater(Base10BigInteger a, Base10BigInteger b)
        {
            if (a.sign != b.sign)
            {
                if ((a.sign == Sign.Negative) && (b.sign == Sign.Positive))
                    return false;

                if ((a.sign == Sign.Positive) && (b.sign == Sign.Negative))
                    return true;
            }

            else
            {
                if (a.sign == Sign.Positive)
                {
                    if (a.size > b.size)
                        return true;
                    if (a.size < b.size)
                        return false;
                    for (int i = (a.size) - 1; i >= 0; i--)
                        if (a.digits[i] > b.digits[i])
                            return true;
                        else if (a.digits[i] < b.digits[i])
                            return false;
                }

                else
                {
                    if (a.size < b.size)
                        return true;
                    if (a.size > b.size)
                        return false;
                    for (int i = (a.size) - 1; i >= 0; i--)
                        if (a.digits[i] < b.digits[i])
                            return true;
                        else if (a.digits[i] > b.digits[i])
                            return false;
                }
            }

            return false;
        }
示例#13
0
 /// <summary>
 /// Smaller or equal test between two Base10BigIntegers.
 /// </summary>
 /// <param name="a">The 1st Base10BigInteger</param>
 /// <param name="b">The 2nd Base10BigInteger</param>
 /// <returns>True if a &lt;= b, false otherwise</returns>
 public static bool SmallerOrEqual(Base10BigInteger a, Base10BigInteger b)
 {
     return(!Greater(a, b));
 }
示例#14
0
 /// <summary>
 /// Greater or equal test between two Base10BigIntegers.
 /// </summary>
 /// <param name="a">The 1st Base10BigInteger</param>
 /// <param name="b">The 2nd Base10BigInteger</param>
 /// <returns>True if a &gt;= b, false otherwise</returns>
 public static bool GreaterOrEqual(Base10BigInteger a, Base10BigInteger b)
 {
     return(Greater(a, b) || Equals(a, b));
 }
示例#15
0
        /// <summary>
        /// Multiplication operation of two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>The Base10BigInteger result of the multiplication</returns>
        public static Base10BigInteger Multiplication(Base10BigInteger a, Base10BigInteger b)
        {
            if ((a == Zero) || (b == Zero))
                return Zero;

            Base10BigInteger res = Multiply(Abs(a), Abs(b));
            if (a.sign == b.sign)
                res.sign = Sign.Positive;
            else
                res.sign = Sign.Negative;

            return res;
        }
示例#16
0
        /// <summary>
        /// Determines whether the specified Base10BigInteger is equal to the current Base10BigInteger.
        /// </summary>
        /// <param name="other">The Base10BigInteger to compare with the current Base10BigInteger</param>
        /// <returns>True if the specified Base10BigInteger is equal to the current Base10BigInteger,
        /// false otherwise</returns>
        public bool Equals(Base10BigInteger other)
        {
            if (sign != other.sign)
                return false;
            if (size != other.size)
                return false;

            for (int i = 0; i < size; i++)
                if (digits[i] != other.digits[i])
                    return false;

            return true;
        }
示例#17
0
 /// <summary>
 /// Smaller or equal test between two Base10BigIntegers.
 /// </summary>
 /// <param name="a">The 1st Base10BigInteger</param>
 /// <param name="b">The 2nd Base10BigInteger</param>
 /// <returns>True if a &lt;= b, false otherwise</returns>
 public static bool SmallerOrEqual(Base10BigInteger a, Base10BigInteger b)
 {
     return !Greater(a, b);
 }
示例#18
0
 /// <summary>
 /// Computes the absolute value of a Base10BigInteger.
 /// </summary>
 /// <param name="n">The Base10BigInteger whose absolute value is to be computed</param>
 /// <returns>The absolute value of the given BigInteger</returns>
 public static Base10BigInteger Abs(Base10BigInteger n)
 {
     Base10BigInteger res = new Base10BigInteger(n);
     res.sign = Sign.Positive;
     return res;
 }
示例#19
0
        /// <summary>
        /// Constructor creating a new Base10BigInteger as a copy of an existing Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger to be copied</param>
        public Base10BigInteger(Base10BigInteger n)
        {
            digits = new long[MaxSize];
            size = n.size;
            sign = n.sign;

            for (int i = 0; i < n.size; i++)
                digits[i] = n.digits[i];
        }
示例#20
0
        /// <summary>
        /// Multiplies two Base10BigIntegers.
        /// </summary>
        private static Base10BigInteger Multiply(Base10BigInteger a, Base10BigInteger b)
        {
            int i, j;
            long temp, trans = 0;

            Base10BigInteger res = new Base10BigInteger();
            res.size = a.size + b.size - 1;
            for (i = 0; i < res.size + 1; i++)
                res.digits[i] = 0;

            for (i = 0; i < a.size; i++)
                if (a.digits[i] != 0)
                    for (j = 0; j < b.size; j++)
                        if (b.digits[j] != 0)
                            res.digits[i + j] += a.digits[i] * b.digits[j];

            for (i = 0; i < res.size; i++)
            {
                temp = res.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans = temp / NumberBase;
            }

            if (trans > 0)
            {
                res.digits[res.size] = trans % NumberBase;
                res.size++;
                trans /= NumberBase;
            }

            return res;
        }
示例#21
0
        /// <summary>
        /// Subtracts the Base10BigInteger b from the Base10BigInteger a, where a >= b, a, b non-negative.
        /// </summary>
        private static Base10BigInteger Subtract(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = new Base10BigInteger(a);
            int i;
            long temp, trans = 0;
            bool reducible = true;

            for (i = 0; i < b.size; i++)
            {
                temp = res.digits[i] - b.digits[i] - trans;
                if (temp < 0)
                {
                    trans = 1;
                    temp += NumberBase;
                }
                else trans = 0;
                res.digits[i] = temp;
            }

            for (i = b.size; ((i < a.size) && (trans > 0)); i++)
            {
                temp = res.digits[i] - trans;
                if (temp < 0)
                {
                    trans = 1;
                    temp += NumberBase;
                }
                else trans = 0;
                res.digits[i] = temp;
            }

            while ((res.size - 1 > 0) && (reducible == true))
            {
                if (res.digits[res.size - 1] == 0)
                    res.size--;
                else reducible = false;
            }

            return res;
        }
示例#22
0
        /// <summary>
        /// Adds two BigNumbers a and b, where a >= b, a, b non-negative.
        /// </summary>
        private static Base10BigInteger Add(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = new Base10BigInteger(a);
            long trans = 0, temp;
            int i;

            for (i = 0; i < b.size; i++)
            {
                temp = res.digits[i] + b.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans = temp / NumberBase;
            }

            for (i = b.size; ((i < a.size) && (trans > 0)); i++)
            {
                temp = res.digits[i] + trans;
                res.digits[i] = temp % NumberBase;
                trans = temp / NumberBase;
            }

            if (trans > 0)
            {
                res.digits[res.size] = trans % NumberBase;
                res.size++;
                trans /= NumberBase;
            }

            return res;
        }
示例#23
0
        /// <summary>
        /// Decremetation by one operation of a Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger to be decremented by one</param>
        /// <returns>The Base10BigInteger result of decrementing by one</returns>
        public static Base10BigInteger operator--(Base10BigInteger n)
        {
            Base10BigInteger res = n - One;

            return(res);
        }
示例#24
0
 /// <summary>
 /// Greater or equal test between two Base10BigIntegers.
 /// </summary>
 /// <param name="a">The 1st Base10BigInteger</param>
 /// <param name="b">The 2nd Base10BigInteger</param>
 /// <returns>True if a &gt;= b, false otherwise</returns>
 public static bool GreaterOrEqual(Base10BigInteger a, Base10BigInteger b)
 {
     return Greater(a, b) || Equals(a, b);
 }
示例#25
0
        /// <summary>
        /// Base10BigInteger inverse with respect to addition.
        /// </summary>
        /// <param name="n">The Base10BigInteger whose opposite is to be computed</param>
        /// <returns>The Base10BigInteger inverse with respect to addition</returns>
        public static Base10BigInteger Opposite(Base10BigInteger n)
        {
            Base10BigInteger res = new Base10BigInteger(n);

            if (res != Zero)
            {
                if (res.sign == Sign.Positive)
                    res.sign = Sign.Negative;
                else
                    res.sign = Sign.Positive;
            }

            return res;
        }
示例#26
0
        /// <summary>
        /// Greater test between two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>True if a &gt; b, false otherwise</returns>
        public static bool Greater(Base10BigInteger a, Base10BigInteger b)
        {
            if (a.sign != b.sign)
            {
                if ((a.sign == Sign.Negative) && (b.sign == Sign.Positive))
                {
                    return(false);
                }

                if ((a.sign == Sign.Positive) && (b.sign == Sign.Negative))
                {
                    return(true);
                }
            }

            else
            {
                if (a.sign == Sign.Positive)
                {
                    if (a.size > b.size)
                    {
                        return(true);
                    }
                    if (a.size < b.size)
                    {
                        return(false);
                    }
                    for (int i = (a.size) - 1; i >= 0; i--)
                    {
                        if (a.digits[i] > b.digits[i])
                        {
                            return(true);
                        }
                        else if (a.digits[i] < b.digits[i])
                        {
                            return(false);
                        }
                    }
                }

                else
                {
                    if (a.size < b.size)
                    {
                        return(true);
                    }
                    if (a.size > b.size)
                    {
                        return(false);
                    }
                    for (int i = (a.size) - 1; i >= 0; i--)
                    {
                        if (a.digits[i] < b.digits[i])
                        {
                            return(true);
                        }
                        else if (a.digits[i] > b.digits[i])
                        {
                            return(false);
                        }
                    }
                }
            }

            return(false);
        }
示例#27
0
        /// <summary>
        /// Constructor creating a new Base10BigInteger as a copy of an existing Base10BigInteger.
        /// </summary>
        /// <param name="n">The Base10BigInteger to be copied</param>
        public Base10BigInteger(Base10BigInteger n)
        {
            digits = new DigitContainer();
            size = n.size;
            sign = n.sign;

            for (int i = 0; i < n.size; i++)
                digits[i] = n.digits[i];
        }
示例#28
0
        /// <summary>
        /// Subtraction operation of two Base10BigIntegers.
        /// </summary>
        /// <param name="a">The 1st Base10BigInteger</param>
        /// <param name="b">The 2nd Base10BigInteger</param>
        /// <returns>The Base10BigInteger result of the subtraction</returns>
        public static Base10BigInteger Subtraction(Base10BigInteger a, Base10BigInteger b)
        {
            Base10BigInteger res = null;

            if ((a.sign == Sign.Positive) && (b.sign == Sign.Positive))
            {
                if (a >= b)
                {
                    res = Subtract(a, b);
                    res.sign = Sign.Positive;
                }
                else
                {
                    res = Subtract(b, a);
                    res.sign = Sign.Negative;
                }
            }

            if ((a.sign == Sign.Negative) && (b.sign == Sign.Negative))
            {
                if (a <= b)
                {
                    res = Subtract(-a, -b);
                    res.sign = Sign.Negative;
                }
                else
                {
                    res = Subtract(-b, -a);
                    res.sign = Sign.Positive;
                }
            }

            if ((a.sign == Sign.Positive) && (b.sign == Sign.Negative))
            {
                if (a >= (-b))
                    res = Add(a, -b);
                else
                    res = Add(-b, a);

                res.sign = Sign.Positive;
            }

            if ((a.sign == Sign.Negative) && (b.sign == Sign.Positive))
            {
                if ((-a) >= b)
                    res = Add(-a, b);
                else
                    res = Add(b, -a);

                res.sign = Sign.Negative;
            }

            return res;
        }