C# (CSharp) SqlParser.Qualified_table_nameContext.table_name示例

示例#1

 public override object VisitQualified_table_name([NotNull] SqlParser.Qualified_table_nameContext context)
 {
     return(new TableName()
     {
         Database = context.database_name() == null ? "" : context.database_name().GetText(),
         Name = EscapeTableOrColumnName(context.table_name() == null ? "" : context.table_name().GetText()),
         Alias = ""
     });
 }