public bool changeProcedure(Type procedureType, string intent, bool addToLastList = true)
{
if (!mSceneProcedureList.TryGetValue(procedureType, out SceneProcedure targetProcedure))
{
logError("can not find scene procedure : " + procedureType);
return(false);
}
// 将上一个流程记录到返回列表中
if (mCurProcedure != null && addToLastList)
{
mLastProcedureList.Add(mCurProcedure);
if (mLastProcedureList.Count > mMaxLastProcedureCount)
{
mLastProcedureList.RemoveAt(0);
}
}
if (mCurProcedure == null || mCurProcedure.getType() != procedureType)
{
// 如果当前已经在一个流程中了,则要先退出当前流程,但是不要销毁流程
if (mCurProcedure != null)
{
// 需要找到共同的父节点,退到该父节点时则不再退出
mCurProcedure.exit(mCurProcedure.getSameParent(targetProcedure), targetProcedure);
}
SceneProcedure lastProcedure = mCurProcedure;
mCurProcedure = targetProcedure;
mCurProcedure.init(lastProcedure, intent);
}
return(true);
}
public bool changeProcedure(PROCEDURE_TYPE procedure, string intent)
{
if (mSceneProcedureList.ContainsKey(procedure))
{
// 将上一个流程记录到返回列表中
if (mCurProcedure != null)
{
mLastProcedureList.Add(mCurProcedure.getType());
}
if (mCurProcedure == null || mCurProcedure.getType() != procedure)
{
SceneProcedure targetProcedure = mSceneProcedureList[procedure];
// 如果当前已经在一个流程中了,则要先退出当前流程,但是不要销毁流程
if (mCurProcedure != null)
{
// 需要找到共同的父节点,退到该父节点时则不再退出
SceneProcedure exitTo = mCurProcedure.getSameParent(targetProcedure);
SceneProcedure nextPro = targetProcedure;
mCurProcedure.exit(exitTo, nextPro);
}
SceneProcedure lastProcedure = mCurProcedure;
mCurProcedure = targetProcedure;
if (mCurProcedure != null)
{
mCurProcedure.init(lastProcedure, intent);
}
}
return(true);
}
else
{
UnityUtility.logError("error : can not find scene procedure : " + procedure);
}
return(false);
}
public void backToLastProcedure(string intend)
{
if (mLastProcedureList.Count == 0)
{
return;
}
// 获得上一次进入的流程
PROCEDURE_TYPE lastType = mLastProcedureList[mLastProcedureList.Count - 1];
if (mSceneProcedureList.ContainsKey(lastType))
{
SceneProcedure targetProcedure = mSceneProcedureList[lastType];
// 先返回到当前流程进入之前的状态
// 需要找到共同的父节点,退到该父节点时则不再退出
SceneProcedure exitTo = mCurProcedure.getSameParent(targetProcedure);
mCurProcedure.back(exitTo);
SceneProcedure lastProcedure = mCurProcedure;
mCurProcedure = targetProcedure;
mCurProcedure.init(lastProcedure, intend);
// 进入上一次的流程后,将流程从返回列表中删除
mLastProcedureList.RemoveAt(mLastProcedureList.Count - 1);
}
else
{
UnityUtility.logError("error : can not back scene procedure");
}
}
// 由GameScene调用
// 进入流程
public void init(SceneProcedure lastProcedure, string intent)
{
// 如果父节点还没有初始化,则先初始化父节点
if (mParentProcedure != null && !mParentProcedure.mInited)
{
mParentProcedure.init(lastProcedure, intent);
}
// 再初始化自己
onInit(lastProcedure, intent);
mInited = true;
}
// 由GameScene调用
// 进入流程
public void init(SceneProcedure lastProcedure, string intent)
{
// 如果父节点还没有初始化,则先初始化父节点
if (mParentProcedure != null && !mParentProcedure.mInited)
{
mParentProcedure.init(lastProcedure, intent);
}
// 再初始化自己,如果是从子节点返回到父节点,则需要调用另外一个初始化函数
if (lastProcedure != null && lastProcedure.isThisOrParent(mProcedureType))
{
onInitFromChild(lastProcedure, intent);
}
else
{
onInit(lastProcedure, intent);
}
mInited = true;
}
public bool changeProcedure(Type procedure, string intent, bool addToLastList = true)
{
if (mSceneProcedureList.ContainsKey(procedure))
{
// 将上一个流程记录到返回列表中
if (mCurProcedure != null && addToLastList)
{
mLastProcedureList.Add(mCurProcedure);
if (mLastProcedureList.Count > mMaxLastProcedureCount)
{
mLastProcedureList.RemoveAt(0);
}
}
if (mCurProcedure == null || mCurProcedure.getProcedureType() != procedure)
{
SceneProcedure targetProcedure = mSceneProcedureList[procedure];
// 如果当前已经在一个流程中了,则要先退出当前流程,但是不要销毁流程
if (mCurProcedure != null)
{
// 需要找到共同的父节点,退到该父节点时则不再退出
SceneProcedure exitTo = mCurProcedure.getSameParent(targetProcedure);
SceneProcedure nextPro = targetProcedure;
mCurProcedure.exit(exitTo, nextPro);
}
SceneProcedure lastProcedure = mCurProcedure;
mCurProcedure = targetProcedure;
mCurProcedure.init(lastProcedure, intent);
}
return(true);
}
else
{
logError("can not find scene procedure : " + procedure);
}
return(false);
}
