C# (CSharp) OneDBox.overlap示例

示例#1

 public int requestStairs(int level, OneDBox igorBox)
 {
     if (!igorBox.overlap(doorBox))
     {
         return(-1);
     }
     if (level > floors)
     {
         return(floors);
     }
     if (level <= 0)
     {
         return(0);
     }
     return(level);
 }

示例#2

文件： Fort.cs 项目： joeygoode/cauldron-command

 public int requestStairs(int level, OneDBox igorBox)
 {
     if (!igorBox.overlap(doorBox))
     {
         return -1;
     }
     if (level > floors)
     {
         return floors;
     }
     if (level <= 0)
     {
         return 0;
     }
     return level;
 }