示例#1
0
            public static NearestPointResult NearestPointOnCurve(Vector2[] b, Vector2 p)
            {
                // convert points to bezier form

                if (b.Length != 4)
                {
                    throw new ArgumentException();
                }

                /*  Convert problem to 5th-degree Bezier form	*/
                Vector2[] w = ConvertToBezierForm(p, b);

                /* Find all possible roots of 5th-degree equation */
                double[] t_candidate = new double[W_DEGREE];
                int      n_soln      = FindRoots(w, W_DEGREE, t_candidate, 0);

                /* Compare distances of P to all candidates, and to t=0, and t=1 */
                double t;
                double dist, new_dist;

                Vector2 p1;

                /* Check distance to beginning of curve, where t = 0	*/
                dist = (p - b[0]).VectorLength2;
                t    = 0;

                /* Find distances for candidate points	*/
                for (int i = 0; i < n_soln; i++)
                {
                    p1       = Bezier(b, DEGREE, t_candidate[i], null, null);
                    new_dist = (p - p1).VectorLength2;
                    if (new_dist < dist)
                    {
                        dist = new_dist;
                        t    = t_candidate[i];
                    }
                }

                /* Finally, look at distance to end point, where t = 1.0 */
                new_dist = (p - b[DEGREE]).VectorLength2;
                if (new_dist < dist)
                {
                    dist = new_dist;
                    t    = 1;
                }

                /*  Return the point on the curve at parameter value t */
                NearestPointResult r = new NearestPointResult();

                r.NearestPoint = Bezier(b, DEGREE, t, null, null);
                r.tval         = t;

                return(r);
            }
示例#2
0
            public static NearestPointResult NearestPointOnCurve(Vector2[] b, Vector2 p)
            {
                // convert points to bezier form

                if (b.Length != 4)
                    throw new ArgumentException();

                /*  Convert problem to 5th-degree Bezier form	*/
                Vector2[] w = ConvertToBezierForm(p, b);

                /* Find all possible roots of 5th-degree equation */
                double[] t_candidate = new double[W_DEGREE];
                int n_soln = FindRoots(w, W_DEGREE, t_candidate, 0);

                /* Compare distances of P to all candidates, and to t=0, and t=1 */
                double t;
                double dist, new_dist;

                Vector2 p1;

                /* Check distance to beginning of curve, where t = 0	*/
                dist = (p - b[0]).VectorLength2;
                t = 0;

                /* Find distances for candidate points	*/
                for (int i = 0; i < n_soln; i++) {
                    p1 = Bezier(b, DEGREE, t_candidate[i], null, null);
                    new_dist = (p - p1).VectorLength2;
                    if (new_dist < dist) {
                        dist = new_dist;
                        t = t_candidate[i];
                    }
                }

                /* Finally, look at distance to end point, where t = 1.0 */
                new_dist = (p - b[DEGREE]).VectorLength2;
                if (new_dist < dist) {
                    dist = new_dist;
                    t = 1;
                }

                /*  Return the point on the curve at parameter value t */
                NearestPointResult r = new NearestPointResult();
                r.NearestPoint = Bezier(b, DEGREE, t, null, null);
                r.tval = t;

                return r;
            }