/// <summary>
/// 查找子节点
/// </summary>
/// <param name="d">子节点的轨迹方向</param>
/// <returns>有相应子节点就返回相应子节点，没有就返回null</returns>
/// 作者：胡皓然
public SkillNode GetChild(InputReceiver.dir d)
{
if (checkChild(d) == -1)
{
return(null);
}
else
{
return(child[checkChild(d)]);
}
}
/// <summary>
/// 确认该结点下是否有某个子节点
/// </summary>
/// <param name="d">子节点方向</param>
/// <returns>有相应子节点就返回子节点下标，没有就返回-1</returns>
/// 作者：胡皓然
int checkChild(InputReceiver.dir d)
{
for (int i = 0; i < child.Count; i++)
{
if (child[i].theDir == d)
{
return(i);
}
}
return(-1);
}
Skill skill; //子技能
public SkillNode(InputReceiver.dir d)
{
theDir = d;
child = new List <SkillNode>();
skill = null;
}
