示例#1
0
        public Query(IBooksDataSource booksDataSource, IAuthorsDataSource authorsDataSource)
        {
            Name = "Query";

            Field <BookType>(
                "book",
                arguments: new QueryArguments(
                    new QueryArgument <NonNullGraphType <IdGraphType> > {
                Name = "id", Description = "id of the book"
            }
                    ),
                resolve: context => booksDataSource.GetBook(context.GetArgument <int>("id"))
                );

            Field <StringGraphType>(
                "bookSource",
                arguments: new QueryArguments(
                    new QueryArgument <NonNullGraphType <IdGraphType> > {
                Name = "id", Description = "id of the book"
            }
                    ),
                resolve: context => JsonConvert.SerializeObject(booksDataSource.GetBook(context.GetArgument <int>("id")))
                );

            Field <ListGraphType <BookType> >(
                "books",
                resolve: context => booksDataSource.GetBooks()
                );

            Field <IntGraphType>(
                "booksCount",
                resolve: context => booksDataSource.GetBooks().Count
                );

            Field <AuthorType>(
                "author",
                arguments: new QueryArguments(
                    new QueryArgument <NonNullGraphType <IdGraphType> > {
                Name = "id", Description = "id of the author"
            }
                    ),
                resolve: context => authorsDataSource.GetAuthor(context.GetArgument <int>("id"))
                );

            Field <StringGraphType>(
                "authorSource",
                arguments: new QueryArguments(
                    new QueryArgument <NonNullGraphType <IdGraphType> > {
                Name = "id", Description = "id of the author"
            }
                    ),
                resolve: context => JsonConvert.SerializeObject(authorsDataSource.GetAuthor(context.GetArgument <int>("id")))
                );

            Field <ListGraphType <AuthorType> >(
                "authors",
                resolve: context => authorsDataSource.GetAuthors()
                );

            Field <IntGraphType>(
                "authorsCount",
                resolve: context => authorsDataSource.GetAuthors().Count
                );
        }
示例#2
0
 public IEnumerable <Author> GetAuthors(ResolveFieldContext context)
 {
     return(authorsDataSource.GetAuthors()
            .Select(a => ConvertToGraphQLAuthor(a, ShouldIncludeBooks(context))));
 }