public IEnumerable <ResourceViewModel> GetResourcesByCategory(string category)
        {
            List <ResourceViewModel> ret = new List <ResourceViewModel>();

            var resources = (from c in _allReadyDataAccess.GetResourcesByCategory(category)
                             select c).Distinct();

            foreach (Resource resource in resources)
            {
                ret.Add(new ResourceViewModel(resource));
            }
            return(ret);
        }
示例#2
0
 public List <Models.Resource> Handle(ResourcesByCategoryQuery message)
 {
     return(dataAccess.GetResourcesByCategory(message.Category).ToList());
 }