C# (CSharp) HttpContent.DeserializeJson示例

示例#1

        public static T DeserializeJsonWithoutToken <T>(this HttpContent content)
        {
            var jsonString = content.DeserializeJson <ApiReturn>();
            var json       = JsonConvert.SerializeObject(jsonString.data);

            return(JsonConvert.DeserializeObject <T>(json));
        }

示例#2

        public static string DeserializeJsonError(this HttpContent content)
        {
            var jsonString = content.DeserializeJson <ApiReturn>();

            return(jsonString.error);
        }