public JsonResult GetExampleModel()
{
try
{
_logger.LogInformation("Get example model");
var exampleModel = _service.GetExampleModel();
return(Json(exampleModel));
}
catch (Exception ex)
{
_logger.LogError(ex.Message);
// This is just one way to do this. There is plenty of other ways to return
// status description and status. One would be to return IActionResult instead of
// JsonResult and give BadRequest.
return(Json(new JsonStatusResponseModel
{
Description = "Error happened in get request",
StatusCode = 400
}));
}
}
