C# (CSharp) EasyWebRequest.SendGetRequestBasedOnHttpClient示例

示例#1

        private async void GetRequest(object sender, EventArgs e)
        {
            string url = "http://192.168.1.102:8077/User/GetThing";
            IDictionary <string, string> routeParames = new Dictionary <string, string>();

            routeParames.Add("str", this.txtInput.Text);
            var result = await EasyWebRequest.SendGetRequestBasedOnHttpClient(url, routeParames);

            var data = (JsonObject)result;

            this.tv.Text = "hey," + data["Val"] + ",  i am from httpclient get";
        }