C# (CSharp) Childs.Find示例

示例#1

        public Node Move(string name)
        {
            if (this.IsLeaf())
            {
                throw new NullReferenceException(nameof(Node));
            }
            var child = Childs.Find(c => c.Name == name);

            if (child is null)
            {
                throw new NullReferenceException(nameof(Node));
            }
            return(child);
        }

示例#2

 public Node ChildByGuid(Guid guid)
 {
     return(Childs.Find(node => node.Guid == guid));
 }

示例#3

 private Node TryChildByLabel(string label)
 {
     return(Childs.Find(node => node.label == label));
 }

示例#4

文件： XmlData.cs 项目： khas7879/pub-framework

 public XmlData SearchChild(System.Predicate <XmlData> func)
 {
     return(Childs.Find(func));
 }