public void OperationsTest()
        {
            BigInteger initial = BigInteger.Parse("4237894523145135423652643587459827");
            BigInteger result0 = initial * 5 * 2 * 10 * 100;
            BigInteger result1 = result0 + 50 + 100;
            BigInteger result2 = result1 / 10;
            BigInteger result3 = result2 - 5;
            BigInteger result4 = result3 * 10 * 1000000;
            BigInteger result5 = result4 - 1;
            BigInteger result6 = result5 / 100;

            var cacheable = new CacheableBigInteger(initial);

            cacheable.Multiply(5);
            cacheable.Multiply(2);
            cacheable.Multiply(10);
            cacheable.Multiply(100);
            cacheable.Add(50);
            cacheable.Add(100);
            cacheable.Divide(10);
            cacheable.Subtract(5);
            cacheable.Multiply(10);
            cacheable.Multiply(BigInteger.Parse("1000000"));
            cacheable.Subtract(BigInteger.Parse("1"));
            cacheable.Divide(BigInteger.Parse("100"));
            Assert.AreEqual(result6, cacheable.Value);
        }
示例#2
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        private static BigInteger CacheableLinear(long n)
        {
            CacheableBigInteger result = 1;

            for (long i = 2; i <= n; i++)
            {
                result.Multiply(i);
            }
            return(result);
        }
        public void OverflowingTest()
        {
            var cacheable = new CacheableBigInteger(0);

            cacheable.Add(long.MaxValue);
            cacheable.Add(1);
            Assert.AreEqual(new BigInteger(long.MaxValue) + 1, cacheable.Value);

            cacheable.Value = new BigInteger(long.MaxValue) + 4;

            cacheable.Subtract(long.MaxValue);
            cacheable.Subtract(4);
            Assert.AreEqual(BigInteger.Zero, cacheable.Value);

            cacheable.Value = 1;

            cacheable.Multiply(long.MaxValue);
            cacheable.Multiply(2);
            Assert.AreEqual(new BigInteger(long.MaxValue) * 2, cacheable.Value);

            cacheable.Divide(long.MaxValue);
            cacheable.Divide(2);
            Assert.AreEqual(BigInteger.One, cacheable.Value);
        }
示例#4
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        private static BigInteger CacheableOptimized(long n)
        {
            CacheableBigInteger result = 1;

            long currentFactor    = n;
            long currentIncrement = currentFactor - 2;

            long bound = n / 2;

            for (long i = 1; i <= bound; i++)
            {
                result.Multiply(currentFactor);

                currentFactor    += currentIncrement;
                currentIncrement -= 2;
            }

            if (n % 2 == 1)
            {
                result.Multiply(n / 2 + 1);
            }

            return(result);
        }