示例#1
0
 /// <summary>
 /// 分词处理器构造函数
 /// </summary>
 /// <param name="input">文本读取流</param>
 public ThesaurusSpliter(TextReader input)
 {
     this.input = input;
     //创建联想流.模仿输入法的联想词语的功能
     assoStream = new AssociateStream();
     ReadBuffer();
 }
示例#2
0
        /// <summary>
        /// 对字符序列进行生词检测
        /// </summary>
        /// <param name="word">字符序列</param>
        /// <param name="length">有效字符数量</param>
        /// <returns></returns>
        public static int Match(Char[] word, int length)
        {
            int nStart = 0;

            //姓氏检测
            if (FamilyNameRule.Test(((int)word[0] << 2) + (int)word[1]))
            {
                nStart = 2;
            }
            else if (FamilyNameRule.Test((int)word[0]) && !LinkRule.Test(word[1]))
            {
                nStart = 1;
            }
            else
            {
                AssociateStream assoStream = new AssociateStream();
                //连词检测,如果不是连词则向后进行词语匹配
                if (!LinkRule.Test(word[1]))
                {
                    for (nStart = 1; nStart < length;)
                    {
                        assoStream.Associate(word[nStart++]);
                        if (!assoStream.IsBegin && assoStream.Associate(word[nStart]))
                        {
                            return(nStart - 1);
                        }
                        else
                        {
                            assoStream.Reset();
                        }
                    }
                }
                //地名检测
                for (nStart = 0; nStart < length - 1;)
                {
                    assoStream.Reset();
                    if (!LinkRule.Test(word[nStart++]) && PlaceRule.Test(word[nStart]))
                    {
                        return(nStart + 1);
                    }
                }
                return(1);
            }
            //如果检测到姓氏并且剩余字符数小于3个字符则整个串是一个完整姓名
            if (length - nStart <= 2)
            {
                return(length);
            }
            //如果串的长度大于姓氏的长度则开始检测有效的名字长度
            if (length > nStart)
            {
                int             nEnd       = nStart + 1;
                AssociateStream assoStream = new AssociateStream();

                //如果下一个字是连接字或者当前字符和下一个字无法组合成一个已知词则将当前字被确认为时姓名的一个字
                if (LinkRule.Test(word[nEnd + 1]) || !(assoStream.Associate(word[nEnd]) && assoStream.Associate(word[nEnd + 1])))
                {
                    nEnd++;
                }
                nStart = nEnd;
            }
            return(nStart);
        }