public void SetData(List <AppointmentRuleVo> appointmentRuleVos, AppointmentModel appointmentModel)
{
//参考GamePlay并且看看CMD的协议
//第一步，读取拉下来的恋爱对象数据
//第二步点击不同的角色进入不同的日记UI。
int[] ids =
{
PropConst.CardEvolutionPropChi, PropConst.CardEvolutionPropQin, PropConst.CardEvolutionPropTang,
PropConst.CardEvolutionPropYan
};
//要优化一下算法了，因为有三重循环在，效率非常低下！
if (ids.Length <= 4)
{
for (int i = 0; i < ids.Length; i++)
{
//_rolesContent.GetChild(i).gameObject.Show();
Image image = _rolesContent.GetChild(i).GetComponent <Image>();
image.alphaHitTestMinimumThreshold = 0.1f;
GameObject redpoint = _rolesContent.GetChild(i).Find("RedPoint").gameObject;
PointerClickListener.Get(_rolesContent.GetChild(i).gameObject).parameter = ids[i];//appointmentRuleVos[i];
PointerClickListener.Get(_rolesContent.GetChild(i).gameObject).onClick = GoToJournal;
//GetTargetData.先获取到AppointmentRule,然后在判断是否有userAppintment在其中，然后每个appointment是否有可解锁的。
//最好的办法就是做一个全局的可解锁条件和全部通关未拍照的条件。
var roleAppointmentRule = appointmentModel.GetTargetData(ids[i]);
bool showredpoint = false;
foreach (var ruleVo in roleAppointmentRule)
{
var userappointment = appointmentModel.GetUserAppointment(ruleVo.Id);
//这个要抽出来做成全局通用的判断！！
if (userappointment == null)
{
continue;
}
//有这张卡并且有红点的时候有两种情况：1.没有激活这张卡。2.有可以解锁的关卡。3.有新的卡
foreach (var v in ruleVo.ActiveCards)
{
showredpoint = appointmentModel.NeedSetRedPoint(userappointment, v);
//Debug.LogError("WHY NO SHOW?");
if (showredpoint)
{
break;
}
}
if (showredpoint)
{
break;
}
}
redpoint.gameObject.SetActive(showredpoint);
}
}
else
{
Debug.LogError(appointmentRuleVos.Count);
}
}
