public ProcessedMessageTrack GetTrackFor(ApplicationInfo applicationInfo)
{
if (applicationInfo.IsNull())
{
throw new ArgumentNullException();
}
return(collection.Find(x => x.ProcessingApplication.ApplicationName == applicationInfo.ApplicationName).FirstOrDefault());
}
public static ProcessedMessageTrack ToMessageTrack(ObjectId eventID, DateTime eventTime, Type messageType, ApplicationInfo application)
{
if (eventID.IsNull() || eventTime.IsNull() || messageType.IsNull() || application.IsNull())
{
throw new ArgumentNullException();
}
return(new ProcessedMessageTrack
{
EventID = eventID,
EventTime = eventTime,
MessageType = messageType.FullName,
ProcessingApplication = application
});
}
public void Subscribe(Subscriber <t> subscriber, ApplicationInfo listenerApplication)
{
if (subscriber.IsNull() || listenerApplication.IsNull())
{
throw new ArgumentNullException();
}
if (!SupportedMessages.GetInstance().IsTypeSupported(typeof(t)))
{
throw new ArgumentException("Type not supported by MessageBus");
}
/**Here assumption is that only subscriber will exist one app context for one type of message.
* if double entry is tried that system will ignore the subscription attempt. It is the
* responsiblity of the caller to ensure that double subscription doesnt happen
*/
if (!this.subscribers.ContainsKey(typeof(t).FullName))
{
MessageMonitor <t> messageMonitors = new MessageMonitor <t>(subscriber, listenerApplication);
this.subscribers.Add(typeof(t).FullName, messageMonitors);
}
}