Пример #1
0
        public void MultiOpAddMul()
        {
            // ({2, 3, 4} + {1, 2, 3}) * 4
            var vector1 = new Vector(new[] { new Number(1), new Number(2), new Number(3) });
            var vector2 = new Vector(new[] { new Number(2), new Number(3), new Number(4) });
            var add = new Add(vector2, vector1);
            var mul = new Mul(add, new Number(4));

            var expected = new Vector(new[] { new Number(12), new Number(20), new Number(28) });
            var result = mul.Calculate();

            Assert.AreEqual(expected, result);
        }
Пример #2
0
        private IExpression SimplifyMul(Mul mul)
        {
            // mul by zero
            if (mul.Left.Equals(zero) || mul.Right.Equals(zero))
                return zero;

            // mul by 1
            if (mul.Left.Equals(one))
                return mul.Right;
            if (mul.Right.Equals(one))
                return mul.Left;

            if (mul.Left is Number && mul.Right is Number)
                return new Number((double)mul.Calculate());

            // 2 * (2 * x)
            // 2 * (x * 2)
            // (2 * x) * 2
            // (x * 2) * 2
            Mul bracketMul = null;
            Number firstNumber = null;
            if (mul.Left is Mul && mul.Right is Number)
            {
                bracketMul = mul.Left as Mul;
                firstNumber = mul.Right as Number;
            }
            else if (mul.Right is Mul && mul.Left is Number)
            {
                bracketMul = mul.Right as Mul;
                firstNumber = mul.Left as Number;
            }
            if (bracketMul != null)
            {
                if (bracketMul.Left is Number)
                {
                    var secondNumber = bracketMul.Left as Number;
                    var result = new Mul(new Number(firstNumber.Value * secondNumber.Value), bracketMul.Right);

                    return _Simplify(result);
                }
                if (bracketMul.Right is Number)
                {
                    var secondNumber = bracketMul.Right as Number;
                    var result = new Mul(new Number(firstNumber.Value * secondNumber.Value), bracketMul.Left);

                    return _Simplify(result);
                }
            }

            // 2 * (2 / x)
            // 2 * (x / 2)
            // (2 / x) * 2
            // (x / 2) * 2
            Div bracketDiv = null;
            if (mul.Left is Div && mul.Right is Number)
            {
                bracketDiv = mul.Left as Div;
                firstNumber = mul.Right as Number;
            }
            else if (mul.Right is Div && mul.Left is Number)
            {
                bracketDiv = mul.Right as Div;
                firstNumber = mul.Left as Number;
            }
            if (bracketDiv != null)
            {
                if (bracketDiv.Left is Number)
                {
                    var secondNumber = bracketDiv.Left as Number;
                    var result = new Div(new Number(firstNumber.Value * secondNumber.Value), bracketDiv.Right);

                    return _Simplify(result);
                }
                if (bracketDiv.Right is Number)
                {
                    var secondNumber = bracketDiv.Right as Number;
                    var result = new Mul(new Number(firstNumber.Value / secondNumber.Value), bracketDiv.Left);

                    return _Simplify(result);
                }
            }

            return mul;
        }
Пример #3
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        public void CalculateTest()
        {
            IExpression exp = new Mul(new Number(2), new Number(2));

            Assert.AreEqual(4.0, exp.Calculate());
        }
Пример #4
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        public void MultiOpMulMul()
        {
            // ({1, 2, 3} * 2) * 4
            var vector = new Vector(new[] { new Number(1), new Number(2), new Number(3) });
            var mul1 = new Mul(vector, new Number(2));
            var mul2 = new Mul(mul1, new Number(4));

            var expected = new Vector(new[] { new Number(8), new Number(16), new Number(24) });
            var result = mul2.Calculate();

            Assert.AreEqual(expected, result);
        }
Пример #5
0
        public void MultiOpSubMul()
        {
            // ({2, 3, 4} - {1, 2, 3}) * 4
            var vector1 = new Vector(new[] { new Number(1), new Number(2), new Number(3) });
            var vector2 = new Vector(new[] { new Number(2), new Number(3), new Number(4) });
            var sub = new Sub(vector2, vector1);
            var mul = new Mul(sub, new Number(4));

            var expected = new Vector(new[] { new Number(4), new Number(4), new Number(4) });
            var result = mul.Calculate();

            Assert.AreEqual(expected, result);
        }