DeSerialize() приватный Метод

private DeSerialize ( ) : IntPtr
Результат System.IntPtr
Пример #1
0
 public XmlNode AddChild(XmlNode child)
 {
     if(child.ElementType == XmlElementType.XML_DOCUMENT_NODE)
     {
     throw new Exception("Document nodes cannot be added anywhere !");
     }
     // clear the cache as this /might/ be freed !
     // I don't take no chances. (wild wild west)
     if(child.ElementType == XmlElementType.XML_TEXT_NODE)
     XmlNodeCache.Uncache(child.DeSerialize());
     IntPtr retval=Native._xmlAddChild(dataPtr,child.DeSerialize());
     if(retval == IntPtr.Zero)
     {
     throw new Exception("New node Could not be linked in !");
     }
     return XmlNodeFactory.NewNode(retval);
 }
Пример #2
0
 public XmlNode AddChild(XmlNode child)
 {
     // clear the cache as this /might/ be freed !
     // I ain't taking no chances. (wild wild west)
     if(this.GetFirstChild()!=null)
     {
     throw new Exception("Cannot add more that one child to a XmlDoc");
     }
     if(child.ElementType==XmlElementType.XML_TEXT_NODE)
     XmlNodeCache.Uncache(child.DeSerialize());
     IntPtr retval=Native._xmlAddChild(dataPtr,child.DeSerialize());
     if(retval == IntPtr.Zero)
     {
     throw new Exception("New node Could not be linked in !");
     }
     return XmlNodeFactory.NewNode(retval);
 }