Пример #1
0
        private static void SelectMany2()
        {
            // flatten the year list to return a list of all racers and positions in the championship
            var racers = Formula1.GetChampionships()
                         .SelectMany(cs => new List <dynamic>()
            {
                new {
                    Year     = cs.Year,
                    Position = 1,
                    Name     = cs.First
                },
                new {
                    Year     = cs.Year,
                    Position = 2,
                    Name     = cs.Second
                },
                new {
                    Year     = cs.Year,
                    Position = 3,
                    Name     = cs.Third
                }
            });


            foreach (var s in racers)
            {
                Console.WriteLine(s);
            }
        }
Пример #2
0
        private static void CombineRacers()
        {
            var q = from r in Formula1.GetChampions()
                    join r2 in Formula1.GetChampionships().GetRacerInfo() on
                    new
            {
                FirstName = r.FirstName,
                LastName  = r.LastName
            }
            equals
            new
            {
                FirstName = r2.FirstName,
                LastName  = r2.LastName
            }
            into yearResults
                select new
            {
                FirstName = r.FirstName,
                LastName  = r.LastName,
                Wins      = r.Wins,
                Starts    = r.Starts,
                Results   = yearResults
            };

            foreach (var item in q)
            {
                Console.WriteLine("{0} {1}", item.FirstName, item.LastName);
                foreach (var item2 in item.Results)
                {
                    Console.WriteLine("{0} {1}", item2.Year, item2.Position);
                }
            }
        }
Пример #3
0
        static void GroupJoin2()
        {
            var racers = Formula1.GetChampionships()
                         .SelectMany(cs => new List <RacerInfo>()
            {
                new RacerInfo
                {
                    Year      = cs.Year,
                    Position  = 1,
                    FirstName = cs.First.FirstName(),
                    LastName  = cs.First.LastName()
                },
                new RacerInfo
                {
                    Year      = cs.Year,
                    Position  = 2,
                    FirstName = cs.Second.FirstName(),
                    LastName  = cs.Second.LastName()
                },
                new RacerInfo
                {
                    Year      = cs.Year,
                    Position  = 3,
                    FirstName = cs.Third.FirstName(),
                    LastName  = cs.Third.LastName()
                }
            });

            var q = (from r in Formula1.GetChampions()
                     join r2 in racers on
                     new
            {
                FirstName = r.FirstName,
                LastName = r.LastName
            }
                     equals
                     new
            {
                FirstName = r2.FirstName,
                LastName = r2.LastName
            }
                     into yearResults
                     select new
            {
                FirstName = r.FirstName,
                LastName = r.LastName,
                Wins = r.Wins,
                Starts = r.Starts,
                Results = yearResults
            });

            foreach (var r in q)
            {
                Console.WriteLine("{0} {1}", r.FirstName, r.LastName);
                foreach (var results in r.Results)
                {
                    Console.WriteLine("{0} {1}", results.Year, results.Position);
                }
            }
        }
Пример #4
0
        // 筛选多个结果
        private static void SelectMany2()
        {
            var racers = Formula1.GetChampionships()
                         .Where(r => r.Year > 2000)
                         .SelectMany(cs => new List <dynamic>() // dynamic 是定义弱对象
                                                                // 自定义对象的属性名
                                                                // 然后用 cs 数据赋值;
                                                                // 将原数据经过封装后, 生成匿名对象返回
            {
                new {
                    Year     = cs.Year,
                    Position = 1,
                    Name     = cs.First,
                    xx       = "hello kitty"
                } /*,
                   * new {
                   * Year = cs.Year,
                   * Position = 2,
                   * Name = cs.Second
                   * }*/
            });

            foreach (var s in racers)
            {
                Console.WriteLine(s);
            }
        }
Пример #5
0
        /* 结果与 下面的 GroupJoin2() 函数相同
         */
        static void GroupJoinLinq()
        {
            var racers = from cs in Formula1.GetChampionships()
                         select new { Year = cs.Year, Numbers = new List <string>()
                                      {
                                          cs.First, cs.Second, cs.Third
                                      } } into temp
            from r in temp.Numbers
                select new { Year = temp.Year, FirstName = r.FirstName(), LastName = r.LastName(), Position = temp.Numbers.IndexOf(r) + 1 };

            var q = (from r in Formula1.GetChampions()      // 只有冠军
                     join r2 in racers on

                     // 临时匿名对象
                     new
            {
                FirstName = r.FirstName,
                LastName = r.LastName
            }
                     equals
                     new
            {
                FirstName = r2.FirstName,
                LastName = r2.LastName
            }
                     into yearResults
                     select new
            {
                FirstName = r.FirstName,
                LastName = r.LastName,
                Wins = r.Wins,
                Starts = r.Starts,
                Results = yearResults
            });

            foreach (var r in q)
            {
                Console.WriteLine("{0} {1}", r.FirstName, r.LastName);
                foreach (var results in r.Results)
                {
                    Console.WriteLine("{0} {1}", results.Year, results.Position);
                }
            }
        }
Пример #6
0
        private static void Except()
        {
            var racers = Formula1.GetChampionships().SelectMany(cs => new List <RacerInfo>()
            {
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 1,
                    FirstName = cs.First.FirstName(),
                    LastName  = cs.First.LastName()
                },
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 2,
                    FirstName = cs.Second.FirstName(),
                    LastName  = cs.Second.LastName()
                },
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 3,
                    FirstName = cs.Third.FirstName(),
                    LastName  = cs.Third.LastName()
                }
            });


            var nonChampions = racers.Select(r =>
                                             new
            {
                FirstName = r.FirstName,
                LastName  = r.LastName
            }).Except(Formula1.GetChampions().Select(r =>
                                                     new
            {
                FirstName = r.FirstName,
                LastName  = r.LastName
            }));

            foreach (var r in nonChampions)
            {
                Console.WriteLine("{0} {1}", r.FirstName, r.LastName);
            }
        }
Пример #7
0
        /*
         * 根据名字列表和 年份123名次, 求出每个名字在<哪年>获得<第几名>
         */
        static void GroupJoin2()
        {
            var racers = Formula1.GetChampionships() // 年份+123名

                                                     /* 把年份 * 1,2,3名 交叉,
                                                      *
                                                      * 将 1950   first   second  third
                                                      * 形成如下格式:
                                                      *  year   pos            name
                                                      * ------------------------------------------
                                                      * 1950     1   first(firstname, lastname)
                                                      * 1950     2   second(firstname, lastname)
                                                      * 1950     3   third(firstname, lastname)
                                                      *
                                                      * 然后用名字列表, 即冠军列表中的名字列表与上表中的  name 作为join 的key
                                                      */
                         .SelectMany(cs => new List <RacerInfo>()
            {
                // 封装年份 + 123名次
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 1,
                    FirstName = cs.First.FirstName(),
                    LastName  = cs.First.LastName()
                },
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 2,
                    FirstName = cs.Second.FirstName(),
                    LastName  = cs.Second.LastName()
                },
                new RacerInfo {
                    Year      = cs.Year,
                    Position  = 3,
                    FirstName = cs.Third.FirstName(),
                    LastName  = cs.Third.LastName()
                }
            });

            var q = (from r in Formula1.GetChampions()      // 只有冠军
                     join r2 in racers on

                     // 临时匿名对象
                     new
            {
                FirstName = r.FirstName,
                LastName = r.LastName
            }
                     equals
                     new
            {
                FirstName = r2.FirstName,
                LastName = r2.LastName
            }
                     into yearResults
                     select new
            {
                FirstName = r.FirstName,
                LastName = r.LastName,
                Wins = r.Wins,
                Starts = r.Starts,
                Results = yearResults
            });

            foreach (var r in q)
            {
                Console.WriteLine("{0} {1}", r.FirstName, r.LastName);
                foreach (var results in r.Results)
                {
                    Console.WriteLine("{0} {1}", results.Year, results.Position);
                }
            }
        }