Пример #1
0
        public void AddContent(PartInfo rel, Stream sourceStream, OpenXmlFormat openXmlFormat)
        {
            PartInfo parentPart = GetPart(rel.RelatedTo);
            PartInfo clonedPart = new PartInfo(this, rel);
            string sContentType;
            if (ContentIsInternalType(rel.Type, openXmlFormat))
            {
                sContentType = rel.GetContentType();
                clonedPart.Target = RemoveLeadingSlash(clonedPart.Target);
                parentPart.AddRelatedItem(clonedPart);
                if (m_partsMap.ContainsKey(clonedPart.AbsolutePath()) && sourceStream == null)
                { // we have already added this content via a relationship elsewhere, don't need to write it
                    return;
                }
                m_partsMap.Add(clonedPart.AbsolutePath(), clonedPart);

                if (sourceStream != null)
                {
                    string partName = clonedPart.AbsolutePath();
                    AddZipEntry(partName, sourceStream);
                    if (rel.ContentTypeOverriden())
                        m_contentTypes.Add("/" + partName, sContentType);
                }
            }
            else
            {//we should only get here for external rels - so there should never be an additional stream to add
                parentPart.AddRelatedItem(clonedPart);
                sContentType = rel.Type;
                if (m_partsMap.ContainsKey(clonedPart.Target))
                { // we have already added this content via a relationship elsewhere, don't need to write it
                    return;
                }
                m_partsMap.Add(clonedPart.Target, clonedPart);
                if (sourceStream != null)
                {
                    throw new System.InvalidOperationException("Sourcestream is not null for supposedly external hyperlink part");
                }
            }
        }