public static BigDecimal Minus(BigDecimal Num1, BigDecimal Num2)
{
//减法运算和加法完全类似
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
if (Rank1 > Rank2)
{
//第一个数字小数点需往右边移动
BigInteger x = IntPart1 * BigInteger.Pow(10, Rank1 - Rank2) - IntPart2;
return(new BigDecimal(x, Rank2));
}
else if (Rank1 < Rank2)
{
//第二个数字小数点需往右边移动
BigInteger x = IntPart1 - IntPart2 * BigInteger.Pow(10, Rank2 - Rank1);
return(new BigDecimal(x, Rank1));
}
else
{
//无需调整
BigInteger x = IntPart1 - IntPart2;
return(new BigDecimal(x, Rank1));
}
}
public static BigDecimal Divide(BigDecimal Num1, BigDecimal Num2)
{
//暂时没有加入四舍五入的考虑
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
if (-Rank1 + Rank2 < Precision + 1)
{
//小于相应精度
//调整被除数的精度
BigInteger x = IntPart1 * BigInteger.Pow(10, Precision + 1 - (Rank2 - Rank1)) / IntPart2;
return(new BigDecimal(x, -(Precision + 1)));
}
else if (-Rank1 + Rank2 > Precision + 1)
{
//大于相应精度
//调整除数的精度
BigInteger x = IntPart1 / (IntPart2 * BigInteger.Pow(10, (Rank2 - Rank1) - (Precision + 1)));
return(new BigDecimal(x, -(Precision + 1)));
}
else
{
return(new BigDecimal(IntPart1 / IntPart2, -(Precision + 1)));
}
}
public static BigDecimal Multiply(BigDecimal Num1, BigDecimal Num2)
{
//BigDecimal 的乘法运算比加减法运算还要简单
//IntPart相乘，阶数相加即可
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
return(new BigDecimal(IntPart1 * IntPart2, Rank1 + Rank2));
}
public static int Compare(BigDecimal Num1, BigDecimal Num2)
{
//1表示Num1 > Num2
//-1表示Num1 < Num2
//0 表示Num1 == Num2
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
int Sign1 = IntPart1.Sign;
int Sign2 = IntPart2.Sign;
//Sign正数返回1，负数返回-1，0返回0
if (Sign1 == 1 && Sign2 == -1)
{
//Num1为正，Num2为负
return(1);
}
else if (Sign1 == -1 && Sign2 == 1)
{
//Num1为负，Num2为正
return(-1);
}
else if (Sign1 == 0 && Sign2 == 0)
{
//Num1为0，Num2为0
return(0);
}
/*int Sign12 = (Num1 - Num2).AcquireIntPart().Sign;
* //直接相减虽然简单，但是速度太慢,以后有空我会进行优化
* if (Sign12 > 0)
* {
* return 1;
* //Num1 > Num2
* }
* else if (Sign12 < 0)
* {
* return -1;
* //Num1 < Num2
* }
* else
* {
* return 0;
* //Num1 == Num2
* }*/
//为了避免转为字符串之后进行比较的尴尬，我想了个办法。。。
if (Rank1 > Rank2)
{
//第一个数字小数点需往右边移动
IntPart1 = IntPart1 * BigInteger.Pow(10, Rank1 - Rank2);
}
else if (Rank1 < Rank2)
{
//第二个数字小数点需往右边移动
IntPart2 = IntPart2 * BigInteger.Pow(10, Rank2 - Rank1);
}
//除此之外无需调整
return(BigInteger.Compare(IntPart1, IntPart2));
}
public static int Compare(BigDecimal Num1, BigDecimal Num2)
{
//1表示Num1 > Num2
//-1表示Num1 < Num2
//0 表示Num1 == Num2
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
int Sign1 = IntPart1.Sign;
int Sign2 = IntPart2.Sign;
//Sign正数返回1，负数返回-1，0返回0
if (Sign1 == 1 && Sign2 == -1)
{
//Num1为正，Num2为负
return 1;
}
else if (Sign1 == -1 && Sign2 == 1)
{
//Num1为负，Num2为正
return -1;
}
else if (Sign1 == 0 && Sign2 == 0)
{
//Num1为0，Num2为0
return 0;
}
/*int Sign12 = (Num1 - Num2).AcquireIntPart().Sign;
//直接相减虽然简单，但是速度太慢,以后有空我会进行优化
if (Sign12 > 0)
{
return 1;
//Num1 > Num2
}
else if (Sign12 < 0)
{
return -1;
//Num1 < Num2
}
else
{
return 0;
//Num1 == Num2
}*/
//为了避免转为字符串之后进行比较的尴尬，我想了个办法。。。
if (Rank1 > Rank2)
{
//第一个数字小数点需往右边移动
IntPart1 = IntPart1 * BigInteger.Pow(10, Rank1 - Rank2);
}
else if (Rank1 < Rank2)
{
//第二个数字小数点需往右边移动
IntPart2 = IntPart2 * BigInteger.Pow(10, Rank2 - Rank1);
}
//除此之外无需调整
return BigInteger.Compare(IntPart1, IntPart2);
}
public static BigDecimal Divide(BigDecimal Num1, BigDecimal Num2)
{
//暂时没有加入四舍五入的考虑
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
if (-Rank1 + Rank2 < Precision + 1)
{
//小于相应精度
//调整被除数的精度
BigInteger x = IntPart1 * BigInteger.Pow(10, Precision + 1 - (Rank2 - Rank1)) / IntPart2;
return new BigDecimal(x, -(Precision + 1));
}
else if (-Rank1 + Rank2 > Precision + 1)
{
//大于相应精度
//调整除数的精度
BigInteger x = IntPart1 / (IntPart2 * BigInteger.Pow(10, (Rank2 - Rank1) - (Precision + 1)));
return new BigDecimal(x, -(Precision + 1));
}
else
{
return new BigDecimal(IntPart1 / IntPart2, -(Precision + 1));
}
}
public static BigDecimal Multiply(BigDecimal Num1, BigDecimal Num2)
{
//BigDecimal 的乘法运算比加减法运算还要简单
//IntPart相乘，阶数相加即可
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
return new BigDecimal(IntPart1 * IntPart2, Rank1 + Rank2);
}
public static BigDecimal Minus(BigDecimal Num1, BigDecimal Num2)
{
//减法运算和加法完全类似
int Rank1 = Num1.AcquireRank();
int Rank2 = Num2.AcquireRank();
BigInteger IntPart1 = Num1.AcquireIntPart();
BigInteger IntPart2 = Num2.AcquireIntPart();
if (Rank1 > Rank2)
{
//第一个数字小数点需往右边移动
BigInteger x = IntPart1 * BigInteger.Pow(10, Rank1 - Rank2) - IntPart2;
return new BigDecimal(x, Rank2);
}
else if (Rank1 < Rank2)
{
//第二个数字小数点需往右边移动
BigInteger x = IntPart1 - IntPart2 * BigInteger.Pow(10, Rank2 - Rank1);
return new BigDecimal(x, Rank1);
}
else
{
//无需调整
BigInteger x = IntPart1 - IntPart2;
return new BigDecimal(x, Rank1);
}
}
