enterIssueForm() публичный Метод

进入BUG和任务详情界面
public enterIssueForm ( string url, string user, string password ) : void
url string
user string
password string
Результат void
Документация по классу Plugin
Пример #1
0
        /// <summary>
        /// 列表项鼠标双击处理
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        private void onListDbClicked(object sender, EventArgs e)
        {
            ListViewItem selectedItem = siteListView.SelectedItems[0];
            int          index        = selectedItem.Index;

            string[] website = dbManage.getWebsites()[index].Split('\t');
            plugin.enterIssueForm(website[0], website[1], website[2]);
        }