Пример #1
0
        public int Solve(string source, string dest)
        {
            if (Dictionary.Where(s => s == source).Count() != 1)
            {
                throw new ArgumentException("source missing in dictionary");
            }

            if (Dictionary.Where(s => s == dest).Count() != 1)
            {
                throw new ArgumentException("dest missing in dictionary");
            }

            if (AdjGraph == null)             // lazy init
            {
                AdjGraph = ConstructAdjancyGraph(Dictionary);
            }

            var data = GraphSearch.BFSTraversal <string>(AdjGraph, source);

            // print path
            Console.WriteLine();
            Console.Write(dest);

            string parent = data[dest].ParentPath;

            while (string.IsNullOrEmpty(parent) == false)
            {
                Console.Write("->" + parent);
                parent = data[parent].ParentPath;
            }

            return(data[dest].Distance + 1);            // including source node
        }
Пример #2
0
        internal string Solve(string[] dependency)
        {
            Dictionary <string, List <string> > adjGraph = null;

            try
            {
                adjGraph = ComputeAdjGraph(dependency);
            }
            catch (Exception ex)
            {
                throw new ArgumentException("dependency", ex);
            }

            var result = GraphSearch.DFSTraversal <string>(adjGraph);

            return(string.Join(Seprator,
                               result.OrderByDescending(s => s.Value.EndTime).Select(s => s.Key)));
        }