Пример #1
0
        /// <summary>
        /// Essential the DIVIDE operator is the inverse of Product
        /// </summary>
        /// <param name="DEND"></param>
        /// <param name="DOR"></param>
        /// <param name="BY"></param>
        /// <returns></returns>
        public static DataTable Divide(DataTable DEND, DataTable DOR, DataColumn BY)

        {
            //First Create Distinct DEND table projected over BY column

            DataTable distinct = SQLOps.Distinct(DEND, BY);

            //Product of distinct and DOR

            DataTable product = SQLOps.Product(distinct, DOR);

            //Difference of product and DEND

            DataTable difference = SQLOps.Difference(product, DEND);

            //Project over BY column

            difference = SQLOps.Project(difference, new DataColumn[] { difference.Columns[BY.ColumnName] });

            //Difference of distinct AND difference

            DataTable table = SQLOps.Difference(distinct, difference);



            table.TableName = "Divide";

            return(table);
        }
Пример #2
0
        /// <summary>
        /// INTERSECT is simply all rows that are in the First table and the Second table
        /// </summary>
        /// <param name="First"></param>
        /// <param name="Second"></param>
        /// <returns></returns>
        /// <remarks>
        /// In summary the code works as follows:<br>
        ///	Get a reference to all columns<br>
        ///	Join on all columns<br>
        ///	Return table<br>
        /// </remarks>
        public static DataTable Intersect(DataTable First, DataTable Second)
        {
            //Get reference to Columns in First

            DataColumn[] firstcolumns = new DataColumn[First.Columns.Count];

            for (int i = 0; i < firstcolumns.Length; i++)

            {
                firstcolumns[i] = First.Columns[i];
            }

            //Get reference to Columns in Second

            DataColumn[] secondcolumns = new DataColumn[Second.Columns.Count];

            for (int i = 0; i < secondcolumns.Length; i++)

            {
                secondcolumns[i] = Second.Columns[i];
            }

            //JOIN ON all columns

            DataTable table = SQLOps.Join(First, Second, firstcolumns, secondcolumns);

            table.TableName = "Intersect";

            return(table);
        }
Пример #3
0
        /// <summary>
        /// Removes the equal rows
        /// </summary>
        /// <param name="Table"></param>
        /// <param name="Columns"></param>
        /// <returns></returns>
        public static DataTable Distinct(DataTable Table, DataColumn[] Columns)

        {
            //Empty table

            DataTable table = new DataTable("Distinct");

            //Sort variable

            string sort = string.Empty;



            //Add Columns & Build Sort expression

            for (int i = 0; i < Columns.Length; i++)

            {
                table.Columns.Add(Columns[i].ColumnName, Columns[i].DataType);

                sort += Columns[i].ColumnName + ",";
            }

            //Select all rows and sort

            DataRow[] sortedrows = Table.Select(string.Empty, sort.Substring(0, sort.Length - 1));



            object[] currentrow = null;

            object[] previousrow = null;



            table.BeginLoadData();

            foreach (DataRow row in sortedrows)

            {
                //Current row

                currentrow = new object[Columns.Length];

                for (int i = 0; i < Columns.Length; i++)

                {
                    currentrow[i] = row[Columns[i].ColumnName];
                }



                //Match Current row to previous row

                if (!SQLOps.RowEqual(previousrow, currentrow))
                {
                    table.LoadDataRow(currentrow, true);
                }



                //Previous row

                previousrow = new object[Columns.Length];

                for (int i = 0; i < Columns.Length; i++)

                {
                    previousrow[i] = row[Columns[i].ColumnName];
                }
            }

            table.EndLoadData();

            return(table);
        }
Пример #4
0
        /// <summary>
        /// Join operator
        /// </summary>
        /// <param name="First"></param>
        /// <param name="Second"></param>
        /// <param name="FJC"></param>
        /// <param name="SJC"></param>
        /// <returns></returns>
        public static DataTable Join(DataTable First, DataTable Second, string FJC, string SJC)

        {
            return(SQLOps.Join(First, Second, new DataColumn[] { First.Columns[FJC] }, new DataColumn[] { Second.Columns[SJC] }));
        }
Пример #5
0
        /// <summary>
        /// Join operator
        /// </summary>
        /// <param name="First"></param>
        /// <param name="Second"></param>
        /// <param name="FJC"></param>
        /// <param name="SJC"></param>
        /// <returns></returns>
        public static DataTable Join(DataTable First, DataTable Second, DataColumn FJC, DataColumn SJC)

        {
            return(SQLOps.Join(First, Second, new DataColumn[] { FJC }, new DataColumn[] { SJC }));
        }